What is 3 4/11 as an improper fraction?

For the graph below, what is the cost per bottle?

motikmotik

17.5$ for every 5 bottles refilled. $3.50 for every 1 bottle refilled

7 0

3 years ago

the functions f and g are defined as follows f(x)=-5x+2 g(x)=3x^2-3x find f(g) and g(-2) simplify your answer as much as possibl

daser333 [38]

Answer:

f(g) = -15x^2 + 15x + 2.

g(-2) = 18.

Step-by-step explanation:

f(g) = -5(3x^2 - 3x) + 2

= -15x^2 + 15x + 2.

g(-2) = 3(-2)^2 - 3(-2)

= 12 + 6

= 18.

8 0

3 years ago

In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir

Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}= p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

(a)

The sample selected is of size n = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0204^{2})$ .

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.96$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size n = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0306^{2})$ .

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.31$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0

3 years ago

Philip's Bagel Shop recently sold 18 bagels, of which 9 were whole wheat bagels. Considering this data, how many of the next 14

lora16 [44]

Answer:Philip's Bagel Shop recently sold 18 bagels, of which 9 were whole wheat bagels. Considering this data, how many of the next 14 bagels sold should you expect to be whole wheat bagels?

Step-by-step explanation:

hahahahahah q

5 0

3 years ago

What is the product of 2 1/8 and 4 1/3

alukav5142 [94]

Answer:

$9\frac{5}{24}$

Step-by-step explanation:

7 0

3 years ago