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N76 [4]
3 years ago
6

Which statement proves that the diagonals of square PQRS are perpendicular bisectors of each other? The length of SP, PQ, RQ, an

d SR are each 5. The slope of SP and RQ is and the slope of SR and PQ is . The length of SQ and RP are both . The midpoint of both diagonals is , the slope of RP is 7, and the slope of SQ is .
Mathematics
2 answers:
MatroZZZ [7]3 years ago
8 0

Answer: the correct answer is letter D, I just took the test and got it right on edg

pochemuha3 years ago
6 0

Answer:

Step-by-step explanation:

Given is a square PQRS.  Its diagonals are PR and QS.

To prove that PR is perpendicular to QS

We have been given as

SP = PQ =RQ =SR =5.

Using Pythagorean theorem we have

both diagonals will equal

5\sqrt2

If P is the origin, (say) then coordinates of vertices would be (0,0) (5,0) (5,5) and (0,5)

Mid point would be (2.5,2.5) for both

Slope of RP = change in y coordinate/change in x coordinate

= 1

Slope of QS = 5/-5 = -1

Product of the two slopes = -1

Hence the two diagonals are perpendicular

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Given that MN = 5, NO = 12, and MO = 13, find cos O.
Galina-37 [17]

Answer:

12/13

Step-by-step explanation:

Given that MN = 5, NO = 12, and MO = 13, find cos O.

Since the reference angle is P, hence;

MN is the opposite = 5

MO is the hypotenuse = 13 (longest side)

NO is the adjacent = 12

Cos O = adj/hyp

Substitute the given values

Cos O = 12/13

Hence the value of Cos O is 12/13

8 0
3 years ago
Need help, extra points
castortr0y [4]

Answer:

around 35-42° it's one of them 2 probably 40-41°

4 0
3 years ago
A culture started with 3000 bacteria. After 4 hours, it grew to 3,600 bacteria. Predict how many bacteria will be present after
Vlad [161]
Hello Shannonrodrigue. You can solve this by setting up an exponential growth equation.

A = A_ob^t
3600 = 3000b^4

Now we solve for b
3600 = 3000b^4
\frac{3600}{3000} = \frac{3000b^{4}}{3000}
\frac{6}{5} = b^4
\sqrt[4]{\frac{6}{5}} = \sqrt[4]{b^4}
\sqrt[4]{\frac{6}{5}} = b

Now that we have found b, we can use the equation A = 3000b^t to predict how many bacteria will be present after 10 hours.
b = \sqrt[4]{\frac{6}{5}}
t = 10
A = 3000b^t
A = 3000\sqrt[4]{\frac{6}{5}}^{10} = 4732.3228 = 4732

Answer = 4732



4 0
3 years ago
What is equivalent to 3 radical 8
liq [111]

Answer:

C. 8^x/3

Step-by-step explanation:

According to algebraic principles, if n is the root of a number, then that number to the power of 1/n is equal to it. This would mean that n√a = a^1/n.

This would mean that 3√8 = 8^1/3. When there is a power added to a radical expression such as this, that power will go on the denominator. So (3√8)^2 for example is equal to 8^2/3, and in your case, (3√8)^x = 8^x/3

looking back on the fact that this was added 2 days ago i dont think this helped on your quiz

6 0
3 years ago
Which of the following equations could be used to find the value of 3,550 ÷ 25?
fiasKO [112]

Answer:

<em>A is correct answer</em>

Step-by-step explanation:

(3000 + 500 + 50) \div 25 \\

(3550) \div 25

=  =  > 3550 \div 25

Thanks

Don't forget to tell the name of your country.

8 0
2 years ago
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