Question

Help me answer this and explain it please! :)

Answer 1

Answer:

90. 04987916

Step-by-step explanation:

Let HI be a

and GH be c

and GI be b

and <GHI be B

Using the law of Cosines,

b^2= -2ac cos (B) + c^2 + a^2

= -2(42)(60) cos (123)+60^2+42^2

= -5040 cos (123) +3600+1764

= -5040(-0. 544639035) +5364

= 2744. 980736+5364

b^2= 8108. 980736

b= Sqrt ( 8108. 980736)

b= 90. 04987916

Answer 2

Answer:

The answer is 99.2

Step-by-step explanation:

The law of cosine states that...

c^2=a^2-2*a*b*cos(theta)

c^2=42^2+60^2-2(42)(60)cos(123)

c^2=1764+3600+4475.36

c=sqrt of 9839.36

c=99.2