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3 years ago

Help me answer this and explain it please! :)

Mathematics

2 answers:

Fynjy0 [20]3 years ago

7 0

Answer:

90. 04987916

Step-by-step explanation:

Let HI be a

and GH be c

and GI be b

and <GHI be B

Using the law of Cosines,

b^2= -2ac cos (B) + c^2 + a^2

= -2(42)(60) cos (123)+60^2+42^2

= -5040 cos (123) +3600+1764

= -5040(-0. 544639035) +5364

= 2744. 980736+5364

b^2= 8108. 980736

b= Sqrt ( 8108. 980736)

b= 90. 04987916

Sphinxa [80]3 years ago

3 0

Answer:

The answer is 99.2

Step-by-step explanation:

The law of cosine states that...

c^2=a^2-2*a*b*cos(theta)

c^2=42^2+60^2-2(42)(60)cos(123)

c^2=1764+3600+4475.36

c=sqrt of 9839.36

c=99.2

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The answer for the exercise shown above is the option B, which is: $x^{7} -4 x^{5} +2 x^{4} +4 x^{3}- 10$
The explanation is shown below:
To list the powers of the polynomial given in the problem above in descending order, you must write the terms from the highest degree to the lowest degree. You have that the highest degree is $7
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2 years ago

Janet has 3 sweatshirts, 5 t-shirts, and 2 pairs of pants that can be worn together. If each outfit has a sweatshirt, t-shirt, a

RideAnS [48]

Answer:

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Step-by-step explanation:

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Have a wonderful day!

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2 years ago

PLEASE HELP ASAP!!!!!!! 1. Calculate the volume of this solid using the formula V=Bh (all angles are 90 degrees).

pshichka [43]

Answer:

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Step-by-step explanation:

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2 years ago

12 Times 12 = 144 right?

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Answer:

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3 years ago

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

2 years ago