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IrinaK [193]
3 years ago
11

How long does it take each horse to run a mile?

Mathematics
1 answer:
ad-work [718]3 years ago
4 0
The fastest racehorses can run a mile in a little over a minute and a half.
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Answer this. I will giveBRAINLIEST​
sweet [91]

Answer:

Multiply both sides by 3, then subtract 6 from both sides

Step-by-step explanation:

d + 6 / 3 = 6 (multiply both sides by 3)

d + 6 = 18 (subtract 6 from both sides)

d = 12

6 0
3 years ago
Read 2 more answers
Select all of the quantities that are correctly expressed in scientific notation
rjkz [21]
The first one and the last one
4 0
3 years ago
If you earn 8 dollars and hour after taxes are taken out of your paycheck and insurance is 200 dollars a month how many hours mu
Luda [366]
To make $200 a month with a 8 dollars p/h salary AFTER taxes. The simple math would just be 200/8 which would equal 25. Hope this helped!
4 0
3 years ago
You went shopping last weekend and bought a new shirt. The shirt had an original price of $39.00 but it was on sale for 35% off
balandron [24]

Answer:

$26.87

Step-by-step explanation:

if the shirt was 35% off, then you paid 65% of the cost

that value can be found by:

39 x .65 = 25.35 (this is the amount paid for the shirt)

sales tax of 6% on 25.35 is:

.06 x 25.35 which equals 1.52

25.35 + 1.52 = 26.87

3 0
2 years ago
Please someone help me...​
laiz [17]

Step-by-step explanation:

First factor out the negative sign from the expression and reorder the terms

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )}  -  \frac{1}{ \cot(6A)  -  \cot(2A) }

<u>Using trigonometric </u><u>identities</u>

That's

<h3>\cot(x)  =  \frac{1}{ \tan(x) }</h3>

<u>Rewrite the expression</u>

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )} -    \frac{1}{ \frac{1}{ \tan(6A) } }  -  \frac{1}{ \frac{1}{ \tan(2A) } }

We have

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{1}{ \frac{ \tan(2A) -  \tan(6A)  }{ \tan(6A) \tan(2A)  } }</h3>

<u>Rewrite the second fraction</u>

That's

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{ \tan(6A)  \tan(2A) }{ \tan(2A) -  \tan(6A)  }</h3>

Since they have the same denominator we can write the fraction as

-  \frac{1 +  \tan(6A) \tan(2A)  }{ \tan(2A) -  \tan(6A)  }

Using the identity

<h3>\frac{x}{y}  =  \frac{1}{ \frac{y}{x} }</h3>

<u>Rewrite the expression</u>

We have

<h3>-  \frac{1}{ \frac{ \tan(2A)  -  \tan(6A) }{1 +  \tan(6A) \tan(2A)  } }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{ \tan(x) -  \tan(y)  }{1 +  \tan(x)  \tan(y) }  =  \tan(x - y)</h3>

<u>Rewrite the expression</u>

That's

<h3>- \frac{1}{ \tan(2A -6A) }</h3>

Which is

<h3>-  \frac{1}{ \tan( - 4A) }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{1}{ \tan(x) }  =  \cot(x)</h3>

Rewrite the expression

That's

<h3>-  \cot( - 4A)</h3>

<u>Simplify the expression using symmetry of trigonometric functions</u>

That's

<h3>- ( -  \cot(4A) )</h3>

<u>Remove the parenthesis </u>

We have the final answer as

<h2>\cot(4A)</h2>

As proven

Hope this helps you

6 0
3 years ago
Read 2 more answers
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