Y = -4/3 + 5 graph it please
2 answers:
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Answer:
The scale factor is
Step-by-step explanation:
Line segmentAB has vertices A(−3, 4) and B(1, −2) .
A dilation, centered at the origin, is applied to AB. The image has vertices
A'(-1,4/3) and B′(1/3, −2/3) .
We know the rule for dilation by scale factor of k, is
This means that;
But we know, A' has coordinates (-1,4/3)
This means that
We could also compare:
4k=4/3
Which gives
k=⅓
ANSWER
A) -1
EXPLANATION
The average rate of change of the given quadratic function on the interval 0 ≤ x ≤4 is the slope of the secant line connecting the points (0,f(0)) and (4,f(4)).
That is the average rate of change is:
From the graph, f(0) is 0 and f(4) is -4.
We plug in these values to obtain;
This simplifies to;
Hence the average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1
A) -1
EXPLANATION
The average rate of change of the given quadratic function on the interval 0 ≤ x ≤4 is the slope of the secant line connecting the points (0,f(0)) and (4,f(4)).
That is the average rate of change is:
From the graph, f(0) is 0 and f(4) is -4.
We plug in these values to obtain;
This simplifies to;
Hence the average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1