All categories

4 years ago

Can someone help my devil of a brother number 2?

Mathematics

1 answer:

Katen [24]4 years ago

8 0

Is that the math question?

You might be interested in

Consider the diagram. What is the length of segment AB?

Sloan [31]

B. 9 I think because it looks like it is bisected in the middle to cut into two equal parts. Please correct me if I am wrong. Thanks.

4 0

3 years ago

Read 2 more answers

I really don't get these questions

Mazyrski [523]

Answer:

Step-by-step explanation:

280 + 5(–5) + (–42) + 2(75) + (–200)

280 - 25 - 42 + 150 - 200

280 - 67 + 150 - 200

280 - 67 - 50

213 - 50

= $163

3 0

3 years ago

17. Evaluate a. 6! b. 8P5 c. 12C4

Andreyy89

The factorial ! just means we multiply by every natural number less that the value so
6! =6×5×4×3×2×1= 720

for permutations we use the formula n!/(n-r)!
so we have 8!/(8-5)!=8!/3!=8×7×6×5×4

for combinations s we have n!/(n-r)!r!
so we have 12!/(12-4)!4!=12!/8!4!=12×11×10×9/4×3×2=11×10×9/2=99×5

7 0

3 years ago

Evaluate: 3y + 1 = 13 + 4y<br> **What do you move first?!**

yan [13]

Answer: isolate the variable

Step-by-step explanation:

5 0

3 years ago

Find the area of the triangle with vertices: q(3,-4,-5), r(4,-1,-4), s(3,-5,-6).

maw [93]

Answer:

(√6)/2 square units

Step-by-step explanation:

The area of a triangle is half the magnitude of the cross product of the vectors representing adjacent sides.

QR = (4-3, -1-(-4), -4-(-5)) = (1, 3, 1)

QS = (3 -3, -5-(-4), -6-(-5)) = (0, -1, -1)

The cross product is the determinant ...

$\text{det}\left|\begin{array}{ccc}i&j&k\\1&3&1\\0&-1&-1\end{array}\right|=-2i+j-k$

The magnitude of this is ...

|QR × QS| = √((-2)² +1² +(-1)²) = √6

The area of the triangle is half this value:

Area = (1/2)√6 . . . . square units

3 0

3 years ago