Answer:
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Step-by-step explanation:
Find the nth term of this number sequence.
2 8 14 20 26
Again write the numbers 1 to 5 above the numbers in the sequence, and leave a spare line again.
n 1 2 3 4 5 (1st row)
(2nd row)
2 8 14 20 26 (3rd row)
Since the sequence is going up by 6, write down your multiples of 6 on the 2nd row.
n 1 2 3 4 5 (1st row)
6n 6 12 18 24 30 (2nd row)
2 8 14 20 26 (3rd row)
Now, to get the numbers in the 3rd row from the 2nd row take off 4.
So, to get from the position numbers (n) to the numbers in the sequence you have to times the position numbers by 6 and take off 4.
Therefore, the nth term = 6n – 4
1.
(3/4)^2 = (3/4)* (3/4)
(3/4)*(3/4)= 9/16
Final answer: 9/16
2.
11+6.4= 17.4
Final answer: 17.4
3.
9.5-2.8= 6.7
Final answer: 6.7
Answer:
The sum is 2635
Step-by-step explanation:
I did this problem
Answer:
-68 is your answer
Step-by-step explanation:
Remember to follow PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)
First, solve each parenthesis
(-21 x 3) = -63
(15/-3) = -5
Next, add
(-63) + (-5) = -63 - 5 = -68
-68 is your answer
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Answer:
(-6,4)
Step-by-step explanation:
The equations are:
Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:
Now we can solve for y:
So plugging in y = 4 into an equation and solving for x, we have:
So y = 4 corresponds to x = 6 & x = -6
The pairs would be
(6,4) & (-6,4)
<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>
