Log(7x+1) - log(x-2) =1
log[(7x+1) / (x-2)] =1 or log[(7x+1) / (x-2)] =log10 (log10=1)
it means (7x+1) / (x-2) =10
Solving ===> x=7
Answer:
y = x/4 + 5
Step-by-step explanation:
Solve for y:
20 - 4 y = -x
Hint: | Isolate terms with y to the left-hand side.
Subtract 20 from both sides:
-4 y = -x - 20
Hint: | Solve for y.
Divide both sides by -4:
Answer: y = x/4 + 5
Answer:1st one 2nd one and 8th
Step-by-step explanation:
Answer:
8% or 0.08
Step-by-step explanation:
Probability of missing the first pass = 40% = 0.40
Probability of missing the second pass = 20% = 0.20
We have to find the probability that he misses both the passes. Since the two passes are independent of each other, the probability that he misses two passes will be:
Probability of missing 1st pass x Probability of missing 2nd pass
i.e.
Probability of missing two passes in a row = 0.40 x 0.20 = 0.08 = 8%
Thus, there is 8% probability that he misses two passes in a row.
Answer:19/20
1-20=19
1÷20=0.05
0.05=5%
I hope this is good enough:
