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lisov135 [29]
3 years ago
5

If five times the successor of a number is added to an original number the sum is 83

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer:

Let the original number be x

Successor is defined as the number which comes immediately after a particular number.

also, the  successor of a whole number is the number obtained by adding 1 to that number.

Then, the successor of a number x is, x+1

As per the given condition :

we have;

5(x+1)+x =83

Using distributive property on LHS (i.e, a\cdot(b+c)=a\cdot b+a\cdot c )

Then, we have

5x+5+x=83

Combine like terms;

6x+5=83

Subtract 5 from both the sides we get;

6x+5-5=83-5

Simplify:

6x=78

Divide both side by 6,

\frac{6x}{6} =\frac{78}{6}

Simplify:

x =13

Therefore, the original number x is, 13


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Answer:

Option A is correct.

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Step-by-step explanation:

Given the expression: \frac{a}{4} = \frac{9}{a}

Cross multiplication the given expression following steps are as follow;

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Using cross multiplication, on the given expression;

\frac{a}{4} = \frac{9}{a}

First multiply the numerator of the left hand fraction(i.e,a ) by the denominator of the right hand fraction (i,e a)

we have;

\frac{a \times a}{4} = 9

Simplify:

\frac{a^2}{4} =9                              [1]

now, multiply numerator of the right-hand fraction( i.e, 9) by the denominator of the left-hand fraction (i.e, 4 ) in [1]

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a^2 = 9\times 4

Simplify:

a^2 = 36

Therefore, the given expression is equal to: a^2 = 36




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