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lisov135 [29]
3 years ago
5

If five times the successor of a number is added to an original number the sum is 83

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer:

Let the original number be x

Successor is defined as the number which comes immediately after a particular number.

also, the  successor of a whole number is the number obtained by adding 1 to that number.

Then, the successor of a number x is, x+1

As per the given condition :

we have;

5(x+1)+x =83

Using distributive property on LHS (i.e, a\cdot(b+c)=a\cdot b+a\cdot c )

Then, we have

5x+5+x=83

Combine like terms;

6x+5=83

Subtract 5 from both the sides we get;

6x+5-5=83-5

Simplify:

6x=78

Divide both side by 6,

\frac{6x}{6} =\frac{78}{6}

Simplify:

x =13

Therefore, the original number x is, 13


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HELP! I am confused since the -5 was added, so would it be the slope or would -7 be the slope?
In-s [12.5K]

Answer:

slope = 35; y-intercept = -45

Step-by-step explanation:

Function f(x) is written in the slope-intercept form, y = mx + b.

f(x) = -7x + 9

You compare it with

f(x) = mx + b, and you see that m, the slope, is -7, and b, the y-intercept is 9.

Now we deal with function h(x).

h(x) = -5(-7x + 9)

This is not written in the y = mx + b form, but we can put it in that form by distributing the -5.

h(x) = 35x - 45

Now, h(x) is written in the y = mx + b form. We see clearly that m = 35, so the slope of function h is 35. We also see that b, the y-intercept is -45.

Answer: slope = 35; y-intercept = -45

5 0
3 years ago
Which is greater 76% or 7/9 or are they bothe equal
Ne4ueva [31]
7/9 is 77.7, as far as I know.
6 0
3 years ago
3x+2y+4+9y=<br> Plz answer
fomenos
<span>3x+2y+4+9y=


Combine like terms:
2y+9y=11y


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3 years ago
Determine whether the statement is true or false.
Citrus2011 [14]

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5 0
3 years ago
Find the derivative of the function f(x) = (x3 - 2x + 1)(x – 3) using the product rule.
julsineya [31]

Answer:

Step-by-step explanation:

Hello, first, let's use the product rule.

Derivative of uv is u'v + u v', so it gives:

f(x)=(x^3-2x+1)(x-3)=u(x) \cdot v(x)\\\\f'(x)=u'(x)v(x)+u(x)v'(x)\\\\ \text{ **** } u(x)=x^3-2x+1 \ \ \ so \ \ \ u'(x)=3x^2-2\\\\\text{ **** } v(x)=x-3 \ \ \ so \ \ \ v'(x)=1\\\\f'(x)=(3x^2-2)(x-3)+(x^3-2x+1)(1)\\\\f'(x)=3x^3-9x^2-2x+6 + x^3-2x+1\\\\\boxed{f'(x)=4x^3-9x^2-4x+7}

Now, we distribute the expression of f(x) and find the derivative afterwards.

f(x)=(x^3-2x+1)(x-3)\\\\=x^4-2x^2+x-3x^3+6x-4\\\\=x^4-3x^3-2x^2+7x-4 \ \ \ so\\ \\\boxed{f'(x)=4x^3-9x^2-4x+7}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0
3 years ago
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