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bija089 [108]
3 years ago
10

Suzi starts her hike at 220 feet below sea level. When she reaches the end of the hike, she is still below sea

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
7 0

Answer:

24 feet

Step-by-step explanation:

(-220)-(-196) = -24\\\\|-24| = 24

Hope this helps, have a great day:)

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Land needs to order supplies for the upcoming month. Her
Dahasolnce [82]

60 of each item

Step-by-step explanation:

5 boxes of pencils, 6 boxes of markers, 15 boxes of notebooks, 10 boxes of erasers, and four boxes of folders

6 0
3 years ago
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Carla withdrew $320 every month for four years to help pay for college how much total money did she withdraw
Julli [10]

Answer:

1280

Step-by-step explanation:

32x4=128

320x4=1280

8 0
3 years ago
What is the perimeter of triangle ABC ?
blagie [28]

Answer:

9+\sqrt{41}

Step-by-step explanation:

From C-A, it goes from y=1 to y=5, so that 4 units

From A-B, it goes from x = -1 to x = 4, that is 5 units

Now, to find distance from B to C, we need to use the distance formula:

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Where the variables are the respective points of B and C,

B (4,5) & C(-1,1)

So x_1 =4, y_1=5, x_2=-1, y_2=1

Plugging into the formula we get:

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\D=\sqrt{(1-5)^2+(-1-4)^2}\\D=\sqrt{16+25}\\ D=\sqrt{41}

Summing it all (perimeter is sum of 3 sides):

Distance = 4+5+\sqrt{41}\\ =9+\sqrt{41}

3rd answer choice is right.

3 0
3 years ago
Pls help me will mark brainliest
iVinArrow [24]

Answer:

34.84

Step-by-step explanation:

5.2 times 6.7= 34.84

5 0
3 years ago
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How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
3 years ago
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