Solve the equation by factoring <br> x^2+x-30=0

Identify the theorem or postulate that is related to the measures of the angles in the pair, and find the unknown angle measures

aleksley [76]

Angles formed when two parallel are intersected by a common transversal include, corresponding, alternate interior and exterior, same-side interior, and vertically opposite angles

The correct option is Same–Side Int. ∠s Thm. m∠1 = 30°, m∠5 = 150°

The reason the selection is correct is as follows:

The given angles are;

m∠1 = (30·x - 30)°. m∠5 = (40·x + 70)°

∠1, and ∠5, are located on the same side of the transversal and are both formed on the interior side of the parallel lines

Therefore, they are same–side interior angles

Same side interior angles theorem states that same side interior angles formed between parallel lines are supplementary

Therefore, we have;

m∠1 + m∠5 = 180°

Which gives;

(30·x - 30)° + (40·x + 70)° = 180°

(70·x + 40)° = 180°

70·x = 180° - 40° = 140°

$x = \dfrac{140^{\circ}}{70} = 2^{\circ}$

m∠1 = (30·x - 30)° = (30 × 2 - 30)° = 30°

m∠1 = 30°

m∠5 = (40·x + 70)° = (40 × 2 + 70)° = 150°

m∠5 = 150°

The correct option is therefore;

Same-Side Int. ∠s Thm. m∠1 = 30°, m∠5 = 150°

Learn more about parallel lines cut by a transversal here:

brainly.com/question/533025

8 0

2 years ago

Mark's soup recipe makes 6 servings and uses 4 carrots and 2 potatoes. Drag carrots and potatoes into the box to show how many M

Vitek1552 [10]

The answer would be 27

7 0

3 years ago

Read 2 more answers

The process of digging a site includes a. carefully recording the location of artifacts. b. accurate descriptions of the artifac

Mice21 [21]

Answer:

The process of digging a site includes

D or B

8 0

3 years ago

Graph the difference between (4.5, -1.5) and (4.5, 7.25)

Gennadij [26K]

Answer:

The difference is 8.75

Step-by-step explanation:

Plot the points or 7.25+1.5=8.75

4 0

2 years ago

Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -

GaryK [48]

Consider all parabolas:

1.

$y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.$

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

2.

$y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.$

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

3.

$y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.$

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

4.

$y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.$

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

5.

$y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.$

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

6.

$y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.$

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0

3 years ago

Solve the equation by factoring x^2+x-30=0