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charle [14.2K]
3 years ago
11

The selling price of a house dropped from $250,000 to $210,000 over a period of 5 years.

Mathematics
1 answer:
AnnyKZ [126]3 years ago
5 0
20% decreased and it needs to increase 40,000 more to get To its normal value
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If a figure has one angle formed from a pair of perpendicular lines, one pair of parallel sides, and no sides with equal lengths
quester [9]

A right trapezoid is a quadrilateral that has exactly one pair of perpendicular lines, one pair of parallel sides, and no sides with equal lengths.

<h3>What is a quadrilateral?</h3>

A quadrilateral is a polygon that has four sides and four angles. Types of quadrilaterals are <em>trapezium, square, rectangle</em> and so on.

A right trapezoid is a quadrilateral that has exactly one pair of perpendicular lines, one pair of parallel sides, and no sides with equal lengths.

Find out more on quadrilateral at: brainly.com/question/23935806

3 0
2 years ago
What is the answer to 2m-6=48
sveticcg [70]
2m=48+6
m=(48+6)/2
m=27
3 0
3 years ago
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PLS ANSWER THIS QUESTION I NEED HELP Will give brainliest
TEA [102]

Answer:

A

Step-by-step explanation:

A, because it has two points which have the same x-value but different y-values, so it cannot be a function.

5 0
3 years ago
What's the y intercept of the following equation?<br> 10y = 20x + 30
nikklg [1K]

Answer:

10y = 20y + 30 \\ y = 2y + 3 \\ y \: intercep = 3

3 0
3 years ago
GEOMETRY 10TH GRADE NEED HELP ASAP
Maru [420]

\boxed{(6, -3)}

Step-by-step explanation:

Given the ratio 5:3

and Points A and B where A is located at (-6, 3), and B is located at (26, -13).

Let point A be (x_{1}, y_{1}), and let point B be (x_{2}, y_{2}).

(-6, 3) → (x_{1}, y_{1}).

(26, -13) → (x_{2}, y_{2}).

Let 5 be n, and 3 be m.

5:3 → n:m

(\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}).

To solve, just substitute these variables into the expressions of these coordinates to get the answer.

(\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}) →

(\frac{(5)x_{1} + (3)x_{2}}{(5)+(3)}, \frac{(5)y_{1} + (3)y_{2}}{(5) + (3)}) →

(\frac{(5)(-6)+ (3)(26)}{(5)+(3)}, \frac{(5)(3)+ (3)(-13)}{(5) + (3)}) →

(\frac{-30 + 78}{8}, \frac{15+ -39}{8}) →

(\frac{78 – 30}{8}, \frac{15 – 39}{8}) →

(\frac{48}{8}, \frac{-24}{8})

→

(\frac{6}{1}, \frac{-3}{1})

→

(6, -3).

Thus the coordinates of B are:

\boxed{(6, -3)}

4 0
3 years ago
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