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bearhunter [10]
3 years ago
13

The intensity (I) of a sound wave varies jointly as the square of its frequency (f), the square of its amplitude (a), the speed

of sound (v), and the density (d) of the substance the wave is traveling through. Which shows this relationship using k as the constant of proportionality? A) k = I f2a2vd B) I = k f2a2vd C) k = If2a2vd D) I = kf2a2vd
Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
5 0
I think that the answer is C
nikdorinn [45]3 years ago
5 0

Answer:

Step-by-step explanation:

the answer is D

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Answer:

The product is :  -\frac{9}{14}

Step-by-step explanation:

First term given to us is =  \frac{3}{4}

Second term given to us = -\frac{6}{7}

We have to find product for term 1 and term 2

Which means that we have to find : (\frac{3}{4})\cdot(-\frac{6}{7})

Calculating the product of fraction is pretty simple. To calculate the product of any two fractions. We have to multiple the numerator of 1st term with numerator of 2nd which serves as the the numerator of the product. Similarly we have to multiply denominator with denominator.

(\frac{3}{4})\cdot(-\frac{6}{7}) = \frac{3\cdot(-6)}{4\cdot7} = -\frac{18}{28}

Reduce the fraction

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How do I solve these?
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