<span>F = 755N, and h = 10.0 m and a = 9.8 m/s^2 and m =? and v = ?To find the mass use F = ma 755 = (m)(9.8) and m = .77 kg then use the formula KE + PE = PE2 + KE2 which is 1/2mv2 + mgh = mgh(2) + 1/2mv2 (2) to solve for the velocity. v1 = 0 and h1 = 10 and v2 = ? and h2 = 0 (1/2)(.77)(0^2) + (.77)(9.8.)(10) = (1/2)(.77)(V2^2) + (.77)(9.8)(0)<span>v=14 m/s</span></span>
Step-by-step explanation:
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The altitude of a triangle is 6 cm greater than its base. If its area is 108 cm
2
. Find its base and height.
Hard
Solution
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Let the base of the triangle be x.
It is given that the altitude of the triangle is 6 cm greater than its base, therefore, the altitude of the triangle is (x+6).
It is also given that the area of the triangle is 108 cm
2
.
We know that the area of the triangle is A=
2
1
×b×a, therefore,
108=
2
1
(x)(x+6)
⇒x
2
+6x=108×2
⇒x
2
+6x=216
⇒x
2
+6x−216=0
⇒x
2
+18x−12x−216=0
⇒x(x+18)−12(x+18)=0
⇒(x−12)=0,(x+18)=0
⇒x=12,x=−18
Since the length of the triangle cannot be negative thus, x=12.
Hence, the base of the triangle is 12 cm
Answer:
Minimum of -9
Step-by-step explanation:
f(x) = (x + 3)(x − 3)
Distribute:
f(x) = x² − 9
In vertex form:
f(x) = 1 (x − 0)² − 9
The leading coefficient is positive, so this is an upwards parabola, meaning the vertex is a minimum. The vertex is at (0, -9). So the minimum of the function is -9.
