Answer:
Step-by-step explanation:
Vi = 30 m /sec
Vf = 0 ( at max. height)
g = - 9.8 m/ sq. sec. ( -ve sign shows that the motion of the body is in opposite direction to that of gravity)
Height it gains=h = ?
Using 3rd equation of kinematics,
2ah=Vf ˄2 – Vi˄2
implies that
h = Vf ˄2 – Vi˄2 / 2a
h = 0˄2 - (30)˄2 / 2(-9.8) = - 900/ -19.6
h = 45.91 m
So the maximum height the body can gain is approximately equal to 46 m.
Note: in simple approximation if we take g = 10 m/ sq.sec then the max. height the body can attain will be 45 m.
3.7k views · View 1 Upvoter · Answer requested by Adele Perriello
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Samuel Lee-Williams
Samuel Lee-Williams, MSci. Physics, The University of Liverpool (2020)
Updated Jun 11, 2019
It's a pretty simple suvat linear projectile motion question, using the following equation and plugging in your values it's a pretty trivial calculation.
V^2=U^2+2*a*x
V=0 (as it is at max height)
U=30ms^-1 (initial speed)
a=-g /-9.8ms^-2 (as it is moving against gravity)
x is the variable you want to calculate (height)
0=30^2+2*(-9.8)*x
x=-30^2/2*-9.8
x=45.92m
