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Romashka-Z-Leto [24]
3 years ago
12

A ball is thrown upward and its height after t seconds can be described by formula f(t)=−10t2+24t+5.6. Find the maximum height t

he ball will reach.

Mathematics
2 answers:
mash [69]3 years ago
6 0

Answer:

Step-by-step explanation:

Vi = 30 m /sec

Vf = 0 ( at max. height)

g = - 9.8 m/ sq. sec. ( -ve sign shows that the motion of the body is in opposite direction to that of gravity)

Height it gains=h = ?

Using 3rd equation of kinematics,

2ah=Vf ˄2 – Vi˄2

implies that

h = Vf ˄2 – Vi˄2 / 2a

h = 0˄2 - (30)˄2 / 2(-9.8) = - 900/ -19.6

h = 45.91 m

So the maximum height the body can gain is approximately equal to 46 m.

Note: in simple approximation if we take g = 10 m/ sq.sec then the max. height the body can attain will be 45 m.

3.7k views · View 1 Upvoter · Answer requested by Adele Perriello

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Samuel Lee-Williams

Samuel Lee-Williams, MSci. Physics, The University of Liverpool (2020)

Updated Jun 11, 2019

It's a pretty simple suvat linear projectile motion question, using the following equation and plugging in your values it's a pretty trivial calculation.

V^2=U^2+2*a*x

V=0 (as it is at max height)

U=30ms^-1 (initial speed)

a=-g /-9.8ms^-2 (as it is moving against gravity)

x is the variable you want to calculate (height)

0=30^2+2*(-9.8)*x

x=-30^2/2*-9.8

x=45.92m

jekas [21]3 years ago
3 0

Answer: 20

Check the image to see my step-by-step explanation!

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