The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

$P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855$

The probability that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0

3 years ago

Complete the table for Lisa hike plzzz help

kipiarov [429]

Answer:

2/3, 1,2,4

Step-by-step explanation:

5 0

2 years ago

How much would it cost to buy 3 $13 battery packs and 3 $22 copper wires

Makovka662 [10]

It would cost $105 because if you do 13+13+13= 39
22+22+22= 66
66+39= 105.

6 0

2 years ago