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mezya [45]
3 years ago
14

Y= 0.5x ANSWER PLEASE!!!

Mathematics
1 answer:
victus00 [196]3 years ago
6 0
I hope this is what you're looking for. Sorry for my writing, I did it with the mouse lol. 

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The thickness of each type of coin is shown in the table. How much thicker is stack of dollars worth of nickels than a dollars w
Lilit [14]
Let our basis be worth 1 dollar. A nickel's worth is $0.05. In order to come up with $1, the number of nickels should be:

Number of nickels = $1 * 1 nickel/$0.05 = 20 nickels
Thickness of 20 nickels = 20 nickels * 1.95 mm = 39 mm

Let's do the same for the quarters. Each quarter is worth $0.25.

Number of quarters = $1 * 1 quarter/$0.25 = 4 quarters
Thickness of 4 quarters = 4 quarters * 1.75 mm = 7 mm

Find the ratio of the two:
39 mm/7 mm = 5.57

Therefore, a stack of nickels is 5.57 times thicker than a stack of quarters worth one dollar.
7 0
3 years ago
If a car is traveling 92 feet per second, how many miles per minute is it traveling?
Jobisdone [24]
It’s A because 92 times 60 is 5520 divide that by the conversion of miles to a foot which is 5280 so 5520 divided by 5280 equals 1.045 or 1.05
7 0
3 years ago
How may pound is 1 ton
SVETLANKA909090 [29]
2,000 IBs (pounds) are in a ton.
3 0
3 years ago
Read 2 more answers
Plss show the work<br> –4z + 8 = –2z
IceJOKER [234]

Answer:

z=-4/3

Step-by-step explanation:

8=-6z

z=-8/6

z=-4/3

4 0
2 years ago
On a unit circle, the vertical distance from the x-axis to a point on the perimeter of the circle is twice the horizontal distan
swat32

Check the picture below.

since the vertical distance, namely the y-coordinate, is twice as much as the horizontal, then if the horizontal is "x", the vertical one must be 2x.

let's find the hypotenuse first.

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{x}\\ b=\stackrel{opposite}{2x}\\ \end{cases} \\\\\\ c=\sqrt{x^2+(2x)^2}\implies c=\sqrt{x^2+4x^2}\implies c=\sqrt{5x^2}\implies c=x\sqrt{5} \\\\[-0.35em] ~\dotfill

\bf sin(\theta )=\cfrac{\stackrel{opposite}{2~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}{\stackrel{hypotenuse}{~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ \sqrt{5}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{\cfrac{2}{\sqrt{5}}\cdot \cfrac{\sqrt{5}}{\sqrt{5}}\implies \cfrac{2\sqrt{5}}{(\sqrt{5})^2}\implies \cfrac{2\sqrt{5}}{5}}

5 0
3 years ago
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