Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;


Divide by m to isolate
.


To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
First solve the area of the arrow, the arrow consist of a rectangle that has a dimensions of 10 ft x 18 ft. and the triangle has a base of 20 ft and the height is 6 ft.
A = xy + 0.5bh
where x and y are the dimensions of the rectangle
b is the base of the triangle
h is the height of the traingle
A = (10)(18) + 0.5(20)(6)
A = 240 sq ft
number can of paint = 240 sq ft ( 1 can / 100 sq ft)
=2.4 can of paint, since you cant purchase a fraction of the can then the he need to buy 3 cans of paint
Hope this helps!
P.S- Can you plz mark min as brainliest??
Thank You
Answer:
A.(-2, 0)
C. (-1.4)
Step-by-step explanation:
we know that
If a point lie on the line, then the point must satisfy the equation of the line (makes the equation true)
we have

subtract 7 both sides


divide by 2 both sides

Substitute the value of x and the value of y of each point in the linear equation and analyze the result
<u><em>Verify each point</em></u>
case A) we have
(-2, 0)
For x=-2, y=0
substitute

---> is true
so
the point lie on the line
case B) we have
(1, 3)
For x=1, y=3
substitute

---> is not true
so
the point not lie on the line
case C) we have
(-1, 4)
For x=-1, y=4
substitute

---> is true
so
the point lie on the line
case D) we have
(1, -4)
For x=1, y=-4
substitute

---> is not true
so
the point not lie on the line
case E) we have
(0, -1)
For x=0, y=-1
substitute

---> is not true
so
the point not lie on the line
Answer:
4356.020
Step-by-step explanation: