The answer is 2x-y
step-by-step explanation
in order to simplify you have to come one like terms and in this case you have your 3x and you’re subtracting x which is also know as 1x.
3x - 1x = 2x (then you still have your y) so 2x-y
2(x+4)^2+4
That is the answer!
Answer:
18) A: only if you have an additional point not on the line.
19) D: No, because all the points may be on the same line.
Step-by-step explanation:
There are basically 4 ways we can determine a plane and they are;
- When we have three non - collinear points: What this means is that if we have three points that are not on one line, then it means that only one particular plane can pass through those points.
- When we have a line and a point that's not on the line
- When we have two lines that intersect each other.
- When we have two lines that are parallel to each other.
From the four conditions above, we can now answer the question;
18) You can only have a plane if there is an additional point not on the line.
Option A
19) Having just three points may not always be sufficient to have a plane because it's possible that the three points may be on the same line which is not a condition for a plane. Thus, option D is correct.
<h2>The distance between two points is
or 9.9 units</h2>
<em><u>Solution:</u></em>
<em><u>The distance between two points is given as:</u></em>
From given,
<em><u>Substituting the values we get,</u></em>
Thus the distance between two points is or 9.9 units
Step-by-step explanation:
First, let's distribute the terms outside each parentheses to get rid of them:
Next, let's move the terms with an 
variable to the left side of the equation, and everything else to the right side:
