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konstantin123 [22]
3 years ago
15

Solve for B 5B-3(4-B)=2(B+21) Much appreciated!!!

Mathematics
2 answers:
Naya [18.7K]3 years ago
6 0
B=-3.18 I hope that helps
slega [8]3 years ago
6 0
I will write it out in steps: 5B-12+3B=2B+42 5B+3B-2B=42+12 6B=54 B=9
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Which of the following is a solution of x2 + 2x + 4?
ivolga24 [154]
Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:

</span>x^2 + 2x + 4= 0.  "Completing the square" seems to be the easiest way to go here:

rewrite   x^2 + 2x + 4  as   x^2 + 2x + 1^2 - 1^2 = -4, or
                                              (x+1)^2 = -3
or                                            x+1 =i*(plus or minus sqrt(3))

or                                            x = -1 plus or minus i*sqrt(3)

This problem, like any other quadratic equation, has two roots.  Note that the fourth possible answer constitutes one part of the two part solution found above.
3 0
3 years ago
3. A charity had a stall at a fair selling crafts and cakes to raise money.
AveGali [126]

15% of £70= £10.5

Expenditure =£24+£10.5=£34.5

Net amount raised =gross amount - Expenditure

=£70-£34.5=£35.5

3 0
3 years ago
What is the solution to the system of equations?
Dovator [93]

Answer:

<h2>(-10, 2, 6)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}x+3y+2z=8&(1)\\3x+y+3z=-10&(2)\\-2x-2y-z=10&(3)\end{array}\right\qquad\text{subtract both sides of the equations (1) from (2)}\\\\\underline{-\left\{\begin{array}{ccc}3x+y+3z=-10\\x+3y+2z=8\end{array}\right }\\.\qquad2x-2y+z=-18\qquad(4)\qquad\text{add both sides of the equations (3) and (4)}\\\\\underline{+\left\{\begin{array}{ccc}-2x-2y-z=10\\2x-2y+z=-18\end{array}\right}\\.\qquad-4y=-8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad y=2\qquad\text{put the value of y to (1) and (3)}

\left\{\begin{array}{ccc}x+3(2)+2z=8\\-2x-2(2)-z=10\end{array}\right\\\left\{\begin{array}{ccc}x+6+2z=8&\text{subtract 6 from both sides}\\-2x-4-z=10&\text{add 4 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+2z=2&\text{multiply both sides by 2}\\-2x-z=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+4z=4\\-2x-z=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad3z=18\qquad\text{divide both sides by 3}\\.\qquad\qquad z=6\qquad\text{put the value of z to the first equation}

x+2(6)=2\\x+12=2\qquad\text{subtract 10 from both sides}\\x=-10

4 0
3 years ago
A rectangle has an are of 36in squared. write an equation to show how length varies inversely the width. what is the equation li
Tju [1.3M]
L*W= 36
Rewrite to get:
l = 36 / w or w = 36 / l
Either one show =s the inverse relationship between w and l
Equation for x and y graph:
y = 36 / x


5 0
3 years ago
Emergency! I don't get this really well. Please help!<br><br>-(8-2n)=8-2(12-3n)
Naddik [55]

Answer:

n = 2

Step-by-step explanation:

2n - 8 = -2 (-3n + 12) + 8

2n - 8 = -(-6n + 24) + 8

2n - 8 = 6n - 24 + 8

2n - 8 = 6n - 16

-4n = -8

Divide each side by 4

n = 2

3 0
3 years ago
Read 2 more answers
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