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erik [133]
3 years ago
11

Enter the slope-intercept equation for the image of line ℓ after a clockwise rotation of 90°. (Hint: To find the image of line ℓ

, choose two or more points on the line and find the images of the points.)​

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
7 0

Answer:

y = -2x - 2

Step-by-step explanation:

From the graph attached,

If the line 'l' passes through two points A(0, -1) and B(4, 1).

Rule for the rotation of any point (x, y), 90° clockwise about the origin is,

(x, y) → (y, -x)

By this rule,

A(0, -1) → A'(-1, 0)

B(4, 1) → B'(1, -4)

Let the equation of the line A'B' is,

y - y' = m(x - x')

where m = slope of the line A'B'

And (x', y') is a point lying on the line.

Slope of the line passing through A' and B' will be,

m = \frac{y_2-y_1}{x_2-x_1}

m = \frac{0+4}{-1-1}

m = -2

Therefore, equation of the line passing through (-1, 0) and slope = -2,

y - 0 = (-2)(x + 1)

y = -2x - 2

So the equation of the line after rotation of lie 'l' by 90° clockwise will be,

y = -2x - 2

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Sauron [17]

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\\

\underline{\underline{\large\bf{Solution:-}}}\\

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\begin{gathered}\\\implies\quad \sf (x-2)(x+8)=0\\\end{gathered}

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\leadstox-intercepts of the given quadratic function are 2 and -8 .

7 0
2 years ago
9/3 *[(18-10)-2^2]<br><br><br>36<br><br>12<br><br>0.25<br><br>0.75
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Answer:

12

Step-by-step explanation:

Use the PEMDAS

there is a parenthesis and exponents

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3 years ago
Minimum point of the quadratic x^2+6x-2
WITCHER [35]

Answer:

(-3,-11)

Step-by-step explanation:

Compare the given quadratic equation with the general quadratic equation.

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Subsitute -3 for x in given quadratic equation.

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The minimum point is (-3,-11).

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2 years ago
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4(x-5)+5y is your answer

5 0
3 years ago
Which line contains the pint (6-4) and has a slope of -5/6
natima [27]

Answer:

y = - 5/6 x + 1

Step-by-step explanation:

y = mx + b      m: slope    b: y intercept

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b = y - mx = -4 - ((-5/6) x 6) = - 4 + 5 = 1

equation: y = - 5/6 x + 1

7 0
3 years ago
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