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2 years ago

What is cos 60 degrees

Mathematics

2 answers:

MakcuM [25]2 years ago

7 0

Answer:

This is a question you should know in trig.

You should search up how to solve for simple trig functions

The cos of 60 degrees is 1/2 just because you asked

BigorU [14]2 years ago

3 0

Answer:

0.5

Step-by-step explanation:

You might be interested in

Negative5 to the negative2 power is what? How do you figure out a negative power?

Paraphin [41]

Scientific NotationDate: 09/16/97 at 00:42:42 From: Aubin Subject: Scientific notation How do you do this problem? I don't understand how you're supposed to get the answer: 5x10 to the 3rd power = 5,000 5x10 to the -3rd power = -5,000 Is this correct? Date: 11/03/97 at 09:56:46 From: Doctor Pipe Subject: Re: Scientific notation Aubin, The first part of what you wrote is correct; 5x10 to the 3rd power = 5,000. The second part is not correct. Writing a negative exponent, such as 10^-3 (read that as ten to the minus third power) is the same as writing 1/(10^3) (read that as one over ten to the third power). Notice that the exponent is negative when writing 10^-3 and positive when writing 1/(10^3) - yet the two numbers are equal. Remember that any number to the zeroeth power, say 10^0, is equal to 1. 10^0 = 1; 5^0 = 1; 275^0 = 1. Remember also that when multiplying two numbers written as base^exponent, if the base in both numbers is equal then we add together the exponents: 10^5 x 10^6 = 10^(5+6) = 10^11. If we have a number 10^5, what number do we multiply it by to get 1? Well, 10^5 x 10^(-5) = 10^(5 + (-5)) = 10^0 = 1. So if 10^5 x 10^(-5) = 1 then 10^(-5) = 1 / 10^5 So, since 10^3 = 1,000 then 10^(-3) = 1/(10^3) = 1/1,000 = 0.001 . It follows from this that: 5x10 to the -3rd power = 5 x 10^(-3) = 5 x 0.001 = 0.005 . The reason for this can be seen by examining what numbers to the right of the decimal point represent. You know what numbers to the left of the decimal point represent: the units digit represents the numeral times 10^0 (any number to the 0th power is 1), the tens digit represents the numeral times 10^1, the hundreds digit represents the numeral times 10^2, and so on. Well, to the right of the decimal point, the tenths digit represents the numeral times 10^-1, the hundredths digit represents the numeral times 10^-2, the thousandths digit represents the numeral times 10^-3, and so on. It's important to understand exponents because exponents allow us to extend the range of numbers that we can work with by allowing us to easily write and work with very large and very small numbers. It's so much easier to write: 10^23 then to write: 100,000,000,000,000,000,000,000 Or to write: 10^(-23) instead of: 0.00000000000000000000001

4 0

3 years ago

The difference when 7 less than a number is subtracted from twice the number is 12. What is the number?

Softa [21]

2n-(n-7)=12
n+7=12
12-7=5
n=5

6 0

3 years ago

There are 10 boys trying out for the track team. Truman and Ryan are the two fastest runners. If the coach randomly picks two bo

vichka [17]

10 kids total

picking Truman would be 1 out of 10 or 1/10

then there would be 9 kids left so picking Ryan would be 1 out of 9 or 1/9

the probability of picking both would be 1/10 * 1/9 = 1/90

5 0

3 years ago

Location is known to affect the number, of a particular item, sold by an automobile dealer. Two different locations, A and B, ar

yKpoI14uk [10]

Answer:

We conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

Step-by-step explanation:

We are given that Location A was observed for 18 days and location B was observed for 13 days.

On average, location A sold 39 of these items with a sample standard deviation of 8 and location B sold 49 of these items with a sample standard deviation of 4.

Let $\mu_1$ = true mean number of sales at location A.

$\mu_2$ = true mean number of sales at location B

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2\geq0$ or $\mu_1 \geq \mu_2$ {means that the true mean number of sales at location A is greater than or equal to the true mean number of sales at location B}

Alternate Hypothesis, $H_A$ : $\mu_1-\mu_2$ or $\mu_1< \mu_2$ {means that the true mean number of sales at location A is fewer than the true mean number of sales at location B}

The test statistics that would be used here Two-sample t test statistics as we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n__1_-_n__2-2$

where, $\bar X_1$ = sample average of items sold at location A = 39

$\bar X_2$ = sample average of items sold at location B = 49

$s_1$ = sample standard deviation of items sold at location A = 8

$s_2$ = sample standard deviation of items sold at location B = 4

$n_1$ = sample of days location A was observed = 18

$n_2$ = sample of days location B was observed = 13

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(18-1)\times 8^{2}+(13-1)\times 4^{2} }{18+13-2} }$ = 6.64

So, test statistics = $\frac{(39-49)-(0)}{6.64 \times \sqrt{\frac{1}{18}+\frac{1}{13} } }$ ~ $t_2_9$

= -4.14

The value of t test statistics is -4.14.

Now, at 0.01 significance level the t table gives critical value of -2.462 at 29 degree of freedom for left-tailed test.

Since our test statistics is less than the critical values of t as -2.462 > -4.14, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

3 0

2 years ago

I don't get it at all 9÷917

Strike441 [17]

You can answer it in fraction or decimal.

Fraction: In fraction, write 9 above 917 like this: 9/917. That is the answer in fraction.

Decimal: In decimal, do the long-division algorithm. You should get 0.009815.

7 0

2 years ago