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marissa [1.9K]
3 years ago
11

Fred can drink 8 and 3/4 sodas in 5 minutes. at this rate how many sodas can fred drink in 2 minutes

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0
Set up a proportion.
(8.75/5)=(x/2)
5x=2*8.75
5x = 17.5
x= 3.5
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In Spetember of 2013, Mario The Baker introduced a new chocolate cake and hired Doug and Jeremy to bake these cakes. Every custo
professor190 [17]

Answer:

There is a 90.32% probability that the cake was baked by Doug.

Step-by-step explanation:

We have these following probabilities:

A 70% probability that Doug bakes the cake.

A 30% probability that Jeremy bakes the cake.

A 40% probability that a cake baked by Doug gets a thumbs up.

A 10% that a cake baked by Jeremy gets a thumbs up.

One cake was selected at random on 10/01/2014 and got a "thumbs up".

1. Find the probability that the cake was baked by Doug.

The probability that a baked cake gets a thumbs up is:

P = 0.7*0.4 + 0.3*0.10 = 0.31

Of those, 0.7*0.4 = 0.28 are baked by Doug.

So the probability is:

P = \frac{0.28}{0.31} = 0.9032

There is a 90.32% probability that the cake was baked by Doug.

4 0
2 years ago
Suppose a population of honey bees in Ephraim, UT has an initial population of 2300 and 12 years later the population reaches 13
Rama09 [41]

Answer:

common ratio: 1.155

rate of growth: 15.5 %

Step-by-step explanation:

The model for exponential growth of population P looks like: P(t)=P_i(1+r)^t

where P(t) is the population at time "t",

P_i is the initial (starting) population

(1+r) is the common ratio,

and r is the rate of growth

Therefore, in our case we can replace specific values in this expression (including population after 12 years, and  initial population), and solve for the unknown common ratio and its related rate of growth:

P(t)=P_i(1+r)^t\\13000=2300*(1+r)^{12}\\\frac{13000}{2300} = (1+r)^12\\\frac{130}{23} = (1+r)^{12}\\1+r=\sqrt[12]{\frac{130}{23} } =1.155273\\

This (1+r) is the common ratio, that we are asked to round to the nearest thousandth, so we use: 1.155

We are also asked to find the rate of increase (r), and to express it in percent form. Therefore we use the last equation shown above to solve for "r" and express tin percent form:

1+r=1.155273\\r=1.155273-1=0.155273

So, this number in percent form (and rounded to the nearest tenth as requested) is: 15.5 %

6 0
2 years ago
-3x=x-(6-2x) explain how asap, please!!
OLEGan [10]
Answer: x=1
-3x=x-6+2x
-6x=-6
x=1
7 0
2 years ago
A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2
andrey2020 [161]

Answer:

The required position of the particle at time t is: x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}

Step-by-step explanation:

Consider the provided matrix.

v_1=\begin{bmatrix}-3\\1 \end{bmatrix}

v_2=\begin{bmatrix}-1\\1 \end{bmatrix}

\lambda_1=4, \lambda_2=2

The general solution of the equation x'=Ax

x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}

Substitute the respective values we get:

x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}

x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}

Substitute initial condition x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}

\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}

Reduce matrix to reduced row echelon form.

\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}

Therefore, c_1=2.5,c_2=1.5

Thus, the general solution of the equation x'=Ax

x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}

x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}

The required position of the particle at time t is: x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}

6 0
3 years ago
35,000,000 what is the order of magnitude of this number
uysha [10]
The anwser is 7 your welcome!
7 0
2 years ago
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