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Alexandra [31]
3 years ago
9

Five times a number is the same as two times a number added 21

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

Our number is 7.

Step-by-step explanation:

We also know that it's 2x + 21 = 5x.

Now we solve.

21 = 5x - 2x

21 = 3x

7 = x

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Zucker Enterprises manufactures painted porcelain dolls. Zucker conducted a time study of the painting task. The painters took f
snow_tiger [21]

Answer:

45 mins

Step-by-step explanation:

The question is how much time should the painter spend on painting a doll for the costs to still be equal or lower to $24.50

We can make this equation, representing the raw materials + the painting job (at $18/h):

$11 + $18x = $24.50

18x = 13.50

x = 13.5 / 18 = 0.75

So, the painter should spend at most 3/4 of an hour (or 45 mins) painting a doll to keep the cost at or below $24.50 per doll.

3 0
3 years ago
1. Suppose you flip a penny 50 times, with 25 tosses landing heads up. What percentage of the tosses would be heads? %​
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Answer:

50%

Step-by-step explanation:

Half of 50 is 25, so when it comes to a percent, half of 100% (50) is 50% (25)

8 0
3 years ago
Given the Arithmetic series A1+A2+A3+A4 7 + 11 + 15 + 19 + . . . + 91 What is the value of sum?
aivan3 [116]

Answer:

The value of the sum is 1078

Step-by-step explanation:

* Lets revise how to find the sum of the arithmetic series

- In the arithmetic series there is a constant difference between each

 two consecutive terms

- Ex:

# 4 , 9 , 14 , 19 , 24 , .......... (+ 5)

# 25 , 15 , 5 , -5 , -15 , .......... (-10)

- So if the first term is a and the constant difference between each two

  consecutive terms is d, then

  U1 = a , U2 = a + d , U3 = a + 2d , U4 = a + 3d , ..........

- Then the nth term is Un = a + (n - 1)d

- The sum of n terms is Sn = n/2[a + L] , where L is the last term in

 the series

* Lets solve the problem

∵ The arithmetic series is 7 + 11 + 15 + 19 + ......................... + 91

∴ The first term (a) is 7

∴ The last term is (L) 91

- Lets find the constant difference

∵ 11 - 7 = 4 and 15 - 11 = 4

∴ The constant difference (d) is 4

- Lets find the sum of the series from 7 to 91

∵ Sn = n/2[a + L]

∵ a = 7 and L = 91

∴ Sn = n/2[7 + 91]

- We need to know how many terms in the series

∵ L is the last term and equals 91 lets find its position in the series

∵ Un = a + (n - 1)d

∵ a = 7 , d = 4 and Un = 91

∴ 91 = 7 + (n - 1)(4) ⇒ subtract 7 from both sides

∴ 84 = (n - 1)(4) ⇒ divide both sides by 4

∴ 21 = n - 1 ⇒ add 1 to both sides

∴ n = 22

∴ The number of the terms in the series is 22

- Lets find the sum of the 22 terms (S22)

∴ S22 = 22/2[7 + 91]

∴S22 = 11[98] = 1078

* The value of the sum is 1078

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