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andriy [413]
3 years ago
9

Use the compound interest formula, . If $10,000 is invested at 2 percent quarterly for 5 years, what is the amount at the end of

the term?
Mathematics
2 answers:
Sonbull [250]3 years ago
4 0
<span>The answer to this question is either 6.16778% or 6%

</span>
mylen [45]3 years ago
4 0
For this case we have the following equation:
 P (t) = P * (1 + r / n) ^ (n * t)
 Where,
 P: initial investment
 r: interest
 n: periods
 t: time
 For 5 years we have:
 P (5) = 10000 * (1 + 0.02 / 4) ^ (4 * 5)
 P (5) = 11048.96 $
 Answer:
 
The amount at the end of the term is:
 
P (5) = 11048.96 $
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in your own words explain the place value relationship when the same two digits are next to each other in a multi digit number
zavuch27 [327]
I'll use 44.  
This number broken down means 4 in the 10's place and 4 in the ones place
 4(10)+4(1)= 40+4=44
4 0
4 years ago
Help me please thank you
harina [27]

I believe it would be 2 units to the right

and 4 units down

7 0
3 years ago
A trucking company uses matrix A , shown below, to represent the driving time in hours for 6 trucking routes. A = [ 4 6 8 ]
zepelin [54]

Each element of the matrix are multiplied by the scalar to form a matrix of

same size as the original matrix in matrix scalar multiplication.

  • 60 \cdot A = \left[\begin{array}{ccc}240\4&360&480\\360&480&600\end{array}\right]

Reasons:

The matrix <em>A</em> is presented as follows;

A = {\left[\begin{array}{ccc}4&6&8\\6&8&10\end{array}\right]}

Using the multiplication of a matrix and a scalar, we have;

60 \cdot A = 60 \cdot  \left[\begin{array}{ccc}4&6&8\\6&8&10\end{array}\right] =  \left[\begin{array}{ccc}60 \times 4&60 \times 6&60 \times 8\\60 \times 6&60 \times 8&60 \times 10\end{array}\right] = \left[\begin{array}{ccc}\mathbf{240}&\mathbf{360}&\mathbf{480}\\\mathbf{360}&\mathbf{480}&\mathbf{600}\end{array}\right]

Therefore;

60 \cdot A = \left[\begin{array}{ccc}240\4&360&480\\360&480&600\end{array}\right]

Learn more about matrices here:

brainly.com/question/14296012

6 0
3 years ago
How many 6 digit different locker combinations are possible if no repeat numbers are allowed?
Alex_Xolod [135]

Since we are trying to find the number of sequences can be made <em>without repetition</em>, we are going to use a combination.


The formula for combinations is:

_n C _k = \dfrac{n!}{k! (n - k)!}

  • n is the total number of elements in the set
  • k is the number of those elements you are desiring

Since there are 10 total digits, n = 10 in this scenario. Since we are choosing 6 digits of the 10 for our sequence, k = 6 in this scenario. Thus, we are trying to find _{10} C _6. This can be found as shown:

_{10} C _6 = \dfrac{10!}{6! \cdot 4!} = \dfrac{10 \cdot 9 \cdot 8 \cdot 7}{4!} = \dfrac{5040}{24} = 210


There are 210 total combinations.

7 0
3 years ago
Write the funniest pick-up line first and I give u brainiest!
N76 [4]

Answer:Feel my shirt. Know what it’s made of? Boyfriend material.” :)

Step-by-step explanation:

5 0
3 years ago
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