2^2x=5^x−1
Take the log pf both sides:
ln(2^2x) = ln(5^x-1)
Expand the logs by pulling the exponents out:
2xln(2) = (x-1)ln(5)
Simpligy the right side:
2xln(2) = ln(5)x - ln(5)
Now solve for x:
Subtract ln(5)x from both sides:
2xln(2) - ln(5)x = -ln(5)
Factor x out of 2xln(2)-ln(5)x
x(2ln(2) - ln(5)) = -ln(5)
Divide both sides by (2ln(2) - ln(5))
X = - ln(5) / (2ln(2) - ln(5))
-4 is the slope in the equation
Answer:
283
Step-by-step explanation:
130+17(9)
130 + 17 times the days
The y factors of the given quadratic equation is -1 and 40/22.
According to the statement
we have given that the equation and we have to find the factors of those equation.
So, The given equation is:

where y is the factors of that equation.
So, we have to find the factors of the given quadratic equation.

Then after solving it become

Then take negative sign common from it then

Make the factors of this quadratic equation

Now take common values 22x and 40 from the equation then

Then it become

Then the values of x become from the equation is

The value of the factors y is -1 and 40/22.
So, The y factors of the given quadratic equation is -1 and 40/22.
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Answer:
-1/2
Step-by-step explanation: