Answer:
First, determine how many standard deviations above the mean one would have to be to be in the 75th percentile. This can be found by using a z table and finding the z associated with 0.75. The value of z is 0.674. Thus, one must be .674 standard deviations above the mean to be in the 75th percentile
Answer:
Tyler is correct. The temperature dropped at a rate of about 4° per hour between 4 and 6, while the temperature dropped at about 2.25° per hour between 6 and 10.
Edit: Explanation
The question is asking about which window of time had a <em>faster</em> decline in temperature, not a larger total change in temperature.
In a 2 hour timeframe, the temperature dropped 8°. (4-6 PM)
In a separate 4 hour timeframe, the temperature dropped 9°. (6-10 PM)
To find which window had a faster change in temp, I took the total temperature drop for each timeframe, then divided it by the number of hours each drop took.
8° / 2 = 4° per hour for 4-6 PM
9° / 4 = 2.25° per hour from 6-10 PM
Since the speed at which the temperature dropped per hour was greater from 4-6 PM than 6-10 PM, Tyler was correct.
Answer:
2 20/24
Step-by-step explanation:
divide 4/2=2
then do 5/8÷3/4=5/8×4/3=20/24
u basically inverse 3/4
2 20/24
Answer:
514 feet
Step-by-step explanation:
Just simply use the pythagorean thereom:
a^2 +b^2 = c^2
put in the values of a, b, and c with the side lengths of the triangle:
x feet, 64 feet, and x+4 feet
x^2 +64^2 = (x+4)^2 , thus x =510
the hypotenuse = x+4 feet = 510 + 4 = 514
ANSWER: 514 feet
