For this case we must find the point that Harold used to arrive at the following equation:

Starting from the fact that the equation of the point-slope form of a line is given by:

If we compare the standard equation with Harold's, we see that the slope of the line is 
In addition, it is observed that
and 
Then, the correct option is: Harold used the point (7,0)
ANswer:
When Harold wrote his equation, the point was used (7,0).
Answer:
10 1/6
Step-by-step explanation:
first get 8 3/4 to a common denominator
8 3/4 *3/3= 8 9/12
8 9/12+ 1 5/12=9 14/12= 10 2/12= 10 1/6
Answer:
3(2x+5)
2*x + 5=15
3*15=45
Step-by-step explanation:
45
Reember taht the antideritive of

is

antiderititive of 4x³=4(x^4)/4=x^4
antideritive of 3x²=3(x³)/3=x³
antiderititive of 6x=6(x²)/2=3x²
antideritiive of 5=5x
f(x)=x⁴+x³-3x²+5x+C
C is answer