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3 years ago

A figure that has no endpoints is called a

Mathematics

1 answer:

dedylja [7]3 years ago

8 0

A figure that has no endpoints is called a line.
Hope this helps you with your homework~!

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For what value of x does (x + 3)^2-5=0

ArbitrLikvidat [17]

Answer:

x = -3±sqrt( 5)

Step-by-step explanation:

(x + 3)^2-5=0

Add 5 to each side

(x + 3)^2-5+5=0+5

(x + 3)^2 = 5

Take the square root of each side

sqrt((x + 3)^2 )=±sqrt( 5)

x+3 = ±sqrt( 5)

Subtract 3 from each side

x+3-3 = -3±sqrt( 5)

x = -3±sqrt( 5)

7 0

3 years ago

If a customer wants to cover an area 20ft wide by 57ft long with rock, how many square feet does he have to cover?

uranmaximum [27]

20*57=1140 ft²
...........................

4 0

3 years ago

Read 2 more answers

Which expression is equivalent to 3 ( x + 10)

devlian [24]

Answer:

3x + 30

Step-by-step explanation:

$3(x+10)\\\\\text{Distribute '3' into 'x + 10'}\\\\\\3(x+10)\rightarrow3x+30\\\\\left \{ {{3*x=3x} \atop {3*10=30}} \right.$

3x + 30 would be an equivalent expression.

Hope this helps.

8 0

3 years ago

A 32-ounce soda costs $4.00 at a movie theater. What is the approximate cost per ounce for the soda?

Rom4ik [11]

Answer:

1 oz of soda costs about $0.13

Step-by-step explanation:

32 oz = $4.00

Divide each side by 32 to simplify.

1 oz = $0.125

$0.125 ≈ $0.13

3 0

2 years ago

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

= Right hand side. (Proved)

7 0

3 years ago