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3 years ago

A figure that has no endpoints is called a

Mathematics

1 answer:

dedylja [7]3 years ago

8 0

A figure that has no endpoints is called a line.
Hope this helps you with your homework~!

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Need help filling in the blanks: selling price using markup.

Xelga [282]

Answer:

Refer to the explanation.

Step-by-step explanation:

Let's take each one at a time.

To solve for the complement, we simply subtract our markup rate by 100%.

100% - 30% = 70%

Now to solve for the selling price, we use the formula

$SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}$

$SellingPrice=\dfrac{86.74}{0.70}$

Selling Price = $123.91

We do the same process with the first number.

100% - 40% = 60%

$SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}$

$SellingPrice=\dfrac{220.00}{0.60}$

SellingPrice = $366.67

The same as the first two.

100% - 20% = 80%

$SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}$

$SellingPrice=\dfrac{89.50}{0.80}$

SellingPrice = $111.88

Now to solve for the markup rate, we use the formula:

$MarkupRate=\dfrac{Markup}{SelingPrice}$

In this case we first need to find the markup. The markup is the difference between the selling price and the cost.

Selling Price = $235.28

Cost = $199.99

Markup = $235.28 - $199.99

Markup = $35.29

Now the we know our markup, we can then solve for the markup rate using the formula.

$MarkupRate=\dfrac{Markup}{SelingPrice}$

$MarkupRate=\dfrac{35.29}{235.28}$

MarkupRate = 0.1499 x 100 = 14.99% or 15%

Now for the last one, we need to find for the cost. Let's use the selling price formula to find for the cost.

$SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}$

Selling Price = $30.77

Complement = 65% or 0.65

This will then give us.

$30.77=\dfrac{Cost}{0.65}$

We multiple both sides of the equation by 0.65 to leave our cost alone.

30.77 x 0.65 = Cost

Cost = $20

4 0

3 years ago

Assume that x equals x (t )and y equals y (t ). Let y equals x cubed plus 4 and StartFraction dx Over dt EndFraction =2 when xe

nika2105 [10]

Answer:dy/dt(x=3)=54

Step-by-step explanation:

We know that we can write:

$\frac{dy}{dt}=\frac{dy}{dx} *\frac{dx}{dt}$

and so evaluate it as a product of functions, that is for a given value of x or t, we get that

$\frac{dy}{dt}(s)=\frac{dy}{dx} (s) * \frac{dx}{dt}(s)$ .

Now we are told that:

$1. x=x(t),\ 2.y=x^3+4,\ \frac{dx}{dt} =2,\ for \ x=3,$

whenever it happens, this means the influence of t is hidden, and we only consider the result, that is, how much is x when the derivative has the value of 2, we are not concerned for what value of t it happens, since we get all the necessary information beforehand.

Now we need to calculate

$\frac{dy}{dx}=3x^2 \rightarrow \frac{dy}{dx}(3)=3(3)^2=27$ .

Therefore

$\frac{dy}{dt}(x=3)=\frac{dy}{dx} (x=3) * \frac{dx}{dt}(x=3)$ or

$\frac{dy}{dt}(x=3)=27 *2 = 54$ .

7 0

4 years ago

Check all the correct solutions

Fynjy0 [20]

A and F are the only set of ordered pairs that work in both of the equations above.

In order to find these you must place them into each equation and check for truth. Below is the work for A and F.

Ordered Pair A : (0,6)

y > 6x + 5
6 > 0 + 5
6 > 5 (TRUE)

y < -6x + 7
6 < 0 + 7
6 < 7 (TRUE)

Ordered Pair F : (-2, 18)

y > 6x + 5
18 > - 12 + 5
18 > -7 (TRUE)

y < -6x + 7
18 < 12 + 7
18 < 19 (TRUE)

7 0

4 years ago

Need help ASAP please! 60 points! -Does anyone have an idea as to how the function should be drawn? I think that there should be

Nesterboy [21]

P(x) to P(x+2), you need to graph the same but shift 2 units to the left.

New function :

Max = 4 ,coordinate points (-5, 0) and (5,0)

6 0

4 years ago

Look at the two points on the number line. Each number

Tatiana [17]

Answer:

√8 and √23

Step-by-step explanation:

4 0

3 years ago