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11Alexandr11 [23.1K]
3 years ago
10

I need help with this problem right away please.

Mathematics
1 answer:
irga5000 [103]3 years ago
7 0

Answer:

y= -1/9(x-1)^2 +2

Step-by-step explanation:

The vertex is at (1,2) and another point is at (-2,1).

We know the vertex form of a parabola is

y= a(x-h)^2 +k  where (h,k) is the vertex  

Substituting the vertex in

y= a(x-1)^2 +2

We have another point, (-2,1)

Substitue this in with x=-2 and y =1.  This will let us find a

1 =  a(-2-1)^2 +2

1 = a (-3)^2 +2

1 = a*9 +2


Subtract 2 from each side

1-2 = 9a +2-2

-1 = 9a

Divide by 9

-1/9 = 9a/9

-1/9 =a

Putting this back into the equation


y= -1/9(x-1)^2 +2

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Sindrei [870]

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width = 9

Step-by-step explanation:

We can use a system of linear equations to solve this problem. Lets make the variable L represent length and W represent width.

So we know that the length is 3 more than the width. An equation for this would be:

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Knowing that W = L - 3, we can replace W in the second equation with L - 3.

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