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professor190 [17]
3 years ago
6

Marcus bought he used 50% on tickets on rides and 1/4 of the tickets on video games and the rest of the tickets in the batting c

age Marcus says he used 24%
Mathematics
1 answer:
GalinKa [24]3 years ago
8 0

Answer:

Therefore Marcus is incorrect.

Step-by-step explanation:

Total ticket that Marcus bought= 100%.

Marcus used 50% of ticket on rides.

and he used  \frac{1}{4} of the tickets on the video games.

The percentage form of any number x is

=100\times x \%

The percentage form of \frac{1}{4} is

=\frac{1\times  100}{4} \%

=25%

Therefore rest tickets are

=Total ticket-( ticket used in rides + ticket used in video games)

=100% - (50%+25%)

=100% - 75%

=25%

Therefore he used 25% of tickets in batting cage.

But he said that Marcus said that he used 24% of ticket in batting cage.

Therefore Marcus is incorrect.

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An investor has an account with stock from two different companies. Last year, her
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Answer:

Final Answer: 19%

Step-by-step explanation: I had the same question, I risked my life and got it wrong for you to get the answer

8 0
3 years ago
Hii can someone help me this is science I didn’t mean to put math and this is 6th grade work btw I’ll give you BRAINLIST if you
algol13

Answer:

Lunar, and solar eclipse!

Step-by-step explanation:

This first one, is pretty easy! An easy way to remember it is solar is sun (both start with s), so lunar is moon!

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6 0
3 years ago
Can you do it quickly
aniked [119]
(I) ||u+v||^2 = <u>
= <u> <u>
= <u>
= ||u||^2 + ||v||^2

(Ii) use what we proved in the first and should be trivial</u></u></u></u>
4 0
3 years ago
Determine whether the three points are collinear. (3, -10), (-2, -7), (0, -5)
Mumz [18]

The points are not collinear.

Solution:

Let A, B and C be (3, -10), (-2, -7) and (0, -5).

<em>If slopes of any two points are same, then the points are collinear.</em>

Slope formula:

$m=\frac{y_2-y1}{x_2-x_1}

<u>Slope of AB:</u>

$m_1=\frac{-7-(-10)}{-2-3}

$m_1=\frac{-7+10}{-5}

$m_1=-\frac{3}{5}

<u>Slope of BC:</u>

$m_2=\frac{-5-(-7)}{0-(-2)}

$m_2=\frac{-5+7}{2}

$m_2=\frac{2}{2}

m_2=1

<u>Slope of CA:</u>

$m_3=\frac{-10-(-5)}{3-0}

$m_3=\frac{-10+5}{3}

$m_3=-\frac{5}{3}

m_1\neq m_2 \neq m_3

Slope of AB ≠ Slope of BC ≠ Slope of AC

Therefore the points are not collinear.

6 0
3 years ago
93 ÷ 10=? using repeated subtraction
aalyn [17]
 93-10=83-10=73-10=63-10=53-10=43-10=33-10=23-10=13-10=3
so 93÷10=9 remainder of 3
5 0
3 years ago
Read 2 more answers
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