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12345 [234]
3 years ago
6

What is 9$ discounted to 4$ in percent form?

Mathematics
1 answer:
faust18 [17]3 years ago
4 0
9 dollars is 4 dollars.
Let's find the percent form of the discount
=> 4 dollars / 9 dollars =  0.44
Now, let's convert it to percentage
=> 0.44 * 100% = 44%
Thus the discount is 44%

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What is the equation of the horizontal asymptote? f(x)=4(52)x+7<br> y=?
natta225 [31]

ANSWER

y=7

EXPLANATION

The horizontal asymptote of an exponential function

f(x)= a {(b)}^{x}  + c

is y=c.

The given exponential function is

f(x)= 4 {(52)}^{x}  + 7

When we compare to

f(x)= a {(b)}^{x}  + c

c=7, therefore the horizontal asymptote is y=7.

4 0
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Solve for a: a(a-3) =100
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5 0
3 years ago
What is the diameter of 80
Trava [24]
What do you mean? just the number 80?
8 0
3 years ago
Read 2 more answers
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
Write the equation in slope-intercept form: answers y=1/2x, y=3x+1/2, y=1/2x+3, y=2x+3
AleksandrR [38]

The equation in the slope-intercept form is:

y = (1/2)*x + 3

<h3>How to write the equation?</h3>

A general linear equation is:

y = a*x + b

Where a is the slope and b is the y-intercept.

To get the slope, we need two points on the line, by using the graph we can identify the points: (0, 3) and (2,4)

Then the slope is:

a = \frac{4 - 3}{2 - 0} = 1/2

And we also can see that the y-intercept is y = 3, because of the point (0,3)

Then the line is:

y = (1/2)*x + 3

If you want to learn more about lines you can read:

brainly.com/question/1884491

#SPJ1

6 0
2 years ago
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