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Paha777 [63]
2 years ago
5

What is the area of 10.5 tall and 9.2 long

Mathematics
1 answer:
mihalych1998 [28]2 years ago
8 0

Answer:

A=LW

A=10.5 x 9.2

A=96.6

Step-by-step explanation:


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Someone plz help meh
gogolik [260]

Answer:

<em>f( g ( - 2 ) ) = - 14 </em>

Step-by-step explanation:

f(x) = - 2x + 4

g(x) = 3x² - x - 5

f( g ( - 2 ) ) = ?

g( - 2 ) = 3( - 2 )² - ( - 2 ) - 5 = 12 + 2 - 5 = 9

f(9) = - 2 × 9 + 4 = - 14

<em>f( g ( - 2 ) ) = - 14</em>

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Step-by-step explanation:

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Rectangle WXYZ was dilated to create W'X'Y'Z'.
Snezhnost [94]

You did not attach any picture to solve this problem. We cannot calculate for the value W’X’ without the correct illustrations. However, I think I found the correct one (see attached), please attach it next time.

So the first thing we have to do is to calculate for the dilation factor. Taking point G as the reference point, we can see that the distance of point G from rectangle W’X’Y’Z’ is 1.5 while the distance from rectangle WXYZ is (1.5 + 7.5), therefore the dilation factor to use is:

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Since WX has an initial measure of 3 units, therefore the measure of W’X’ is:

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<span>0.5 units</span>

4 0
2 years ago
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Which numbers is 90 divisible by
SIZIF [17.4K]

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If master chief has three and a half cookies, and the arbiter has five and three quarters of a cookie, how many cookies do they
nikklg [1K]

Answer:

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4\dfrac{5}{8}

Step-by-step explanation:

The master chief has three and a half cookies i.e. 3\dfrac{1}{2} = \dfrac{7}{2} numbers of cookies.

Again the arbiter has five and three quarters of a cookie i.e. 5\dfrac{3}{4} = \dfrac{23}{4} number of cookies.

Therefore, in total there are (\dfrac{7}{2} +\dfrac{23}{4} ) = \dfrac{37}{4} = 9\dfrac{1}{4} numbers of cookies.

If we divide the total number of cookies in to equal parts and distribute to then then each of them will get \dfrac{37}{4 \times 2} = \dfrac{37}{8} = 4\dfrac{5}{8} numbers of cookies. (Answer)  

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