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MakcuM [25]
1 year ago
7

Consider the function f(x) = x² + 10x + 25 for x ≥ -5. What is the value of f-¹(x) when x = 4?

Mathematics
1 answer:
prisoha [69]1 year ago
5 0

Answer:

-3

Step-by-step explanation:

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A printing company’s costs for printing a book are $500 for labor and running the necessary machinery plus $3 per book printed.
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The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of
ser-zykov [4K]

Answer:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}, for r_{1} = 0

Step-by-step explanation:

The general form of quintic-order polynomial is:

p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f

According to the statement of the problem, the polynomial has the following roots:

p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)

Then, some algebraic handling is done to expand the polynomial:

p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)

p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x

If r_{1} = 0, then:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}

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3 years ago
what is an equationof the line that passes through the points (0,-7) and (-8,3) put your answer in fully reduced form pleaseee h
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Answer:

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Step-by-step explanation:

First, find the slope:

3 - -7 / -8 - 0 = -5/4

Put it in point slope form:

y + 7 = -5/4(x-0)

y + 7 = -5/4x

y = -5/4x - 7

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Find the missing values to the solution y = 2/3x + 5
trapecia [35]

Answer:

you would need more info... do you have any more information for this question?

Step-by-step explanation:

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