Answer: choice A) 7017
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Work Shown:
The first term is a_1 = 24 and we go up by 7 each time.
The common difference is d = 7
The nth term formula we'll use is
a_n = a_1 + (n-1)*d
a_n = 24 + (n-1)*7
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The 1000th term corresponds to n = 1000
Replace every n with 1000
Then use the order of operations (PEMDAS) to simplify
a_n = 24 + (n-1)*7
a_1000 = 24 + (1000-1)*7
a_1000 = 24 + (999)*7
a_1000 = 24 + 6993
a_1000 = 7017
Answer:
Approximate probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is less than 0.0005% .
Step-by-step explanation:
We are given that let X be the number that do some or all of their banking on the Internet.
Also; Mean,
= 310/1000 or 0.31 and Standard deviation,
= 14.63/1000 = 0.01463 .
We know that Z =
~ N(0,1)
Probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is given by P(X <= 130/1000);
P(X <=0.13) = P(
<=
) = P(Z <= -12.303) = P(Z > 12.303)
Since this value is not represented in the z table as the value is very high and z table is limited to x = 4.4172.
So, after seeing the table we can say that this probability is approximately less than 0.0005% .
I think it is 60 years old?
Answer:
y = -1/2x - 3
Step-by-step explanation:
slope: (y2-y1) / (x2-x1)
(-5 - -2) / (4 - -2)
(-5 + 2) / (4 + 2)
-3 / 6
- 1 / 2
y-intercept: y = mx + b
-5 = -1/2(4) + b
-5 = -2 + b
-3 = b