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Zanzabum
3 years ago
9

Which point is on the graph of f(x) = 3.5%? A. (1,15) B. (0, 15) C. (15,1) D. (0,0)

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

Answer:

b.)

Step-by-step explanation:

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Help answer asap pls ---------
Reika [66]

Answer:

d = 5

Step-by-step explanation:

We want to know what d would be when x = -1, so we can start off by plugging in -1 for x to get the following equation: \sqrt{8 - (-1)} = 2(-1)+d. On the left hand side, 2 negatives become a positive sign, so the -(-1) becomes a +1, and 8+1 would equal 9. On the right hand side, we just multiply 2 and -1 to get -2. So, the equation now looks like this: \sqrt{9} = d-2. We know that \sqrt{9} = 3, so we would get 3 = d-2. THen we would add 2 to both sides to get d = 5. Hope this helps!

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3 years ago
Which symbol correctly compares the two fractions? Use > , < , or =. Enter your answer in the box. 2/3 4/6
SVEN [57.7K]
The correct answer is = because 4/6 simplifies to 2/3
4 0
4 years ago
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Can somebody tell me how to solve these kind of problems?
Ugo [173]

Answer: 918km^2

Step-by-step explanation:

area(a): 1700km^2\\percentage(p): 5.75 = \frac{5.75}{100}=0.0575\\years(y): 8

Let x be the new dimension of the area;

x=a-(a*p*y)

x=(1700km^2)-(1700km^2*0.0575*8)\\x=1700km^2-782km^2\\x=918km^2

6 0
3 years ago
Select all the situations that can be represented by the tape diagram. 99 W W W W W 4 Clare buys 4 bouquets, each with the same
enot [183]

Answer:

Third one 33333333333333333

5 0
3 years ago
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An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

5 0
2 years ago
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