Question

Solve: In 2x + In 2 = 0 DONE

Answer 1

Answer:

$x=\frac{1}{4}$

Step-by-step explanation:

We can use some logarithmic rules to solve this easily.

Note: Ln means $Log_e$

Now, lets start with the equation:

$ln(2x) + ln(2) = 0\\ln(2x) = -ln(2)$

Writing left side with logarithmic base e, we have:

$Log_{e}(2x) = -ln(2)$

We can now use the property shown below to make this into exponential form:

$Log_{a}b=x\\means\\a^x=b$

So, we write:

$Log_{e}(2x) = -ln(2)\\e^{-ln(2)}=2x$

We recognize another property of exponentials:

$a^{bc}=(a^{b})^{c}$

So, we write:

$e^{-ln(2)}=2x\\(e^{ln(2)})^{-1}=2x$

Also, another property of natural logarithms is:

$e^{(ln(a))}=a$

Now, we simplify:

$(e^{ln(2)})^{-1}=2x\\(2)^{-1}=2x\\\frac{1}{2}=2x\\x=\frac{\frac{1}{2}}{2}\\x=\frac{1}{4}$

This is the answer.