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seropon [69]
3 years ago
5

Six friends, four boys and two girls, went to a movie theater. They wanted to sit in a way so no girl sits on either first or la

st chair. How many such arrangements are possible?
Mathematics
1 answer:
mel-nik [20]3 years ago
8 0

Answer:

120 ways

Step-by-step explanation:

Since no girl wil sit either first or last

Hence, in all irrespective whether boy or girl = (6 - 1)! = 5! = 5 X 4 X 3 X 2 = 120

∴ Number of arrangements = 120 ways

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