In the equation t = d/6+3 what is the value of t when d =12

2 answers:

7 0

T=d/6+3
1. Fill in: t=12/6+3
2. Remember PEMDAS!! P(parenthesis)E(Exponents)M(multiply)D(divide)A(add)S(subtract)
So, you will divide 12 by 6 first, which equals out to 2.
3. Write your new equation: t=2+3
4. Add 2+3, which equals to 5.

t=5

leonid [27]3 years ago

4 0

So you know d= 12
Therefore, you sub it into the equation which will be:
t= 12/6 +3
Using bedmas we know we divide first, 12/6 is 2, therefore that will be 2, then you add that to 3 and you get 5.
t= 5

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Do the product 40x500 and 40x600 have the same number of zeros

VARVARA [1.3K]

No they do not have the same number of zeroes

Although the 2 products do seem like they might have the same number of zeroes, 40 x 500 and 40 x 600

both have 3 zeroes before multiplying

if we take the first 2 digits of the 2 numbers being multiplied to get an idea of the answer

if we take 40 x 500 - 4 x 5 = 20

then theres an extra zero added

but if we take 40 x 600 - 4 x 6 = 24

no extra zeroes added to this

so if we finally look at the answers

40 x 500 = 20 000

40 x 600 = 24 000

20000 has 4 zeroes and 24000 has 3 zeroes

so the answer is no they dont have the same number of zeroes

8 0

4 years ago

Read 2 more answers

Write the next three terms of the arithmetic sequence.

JulijaS [17]

The next three terms are: 1/6 , 0 and -1/6

Step-by-step explanation:

Given sequence is:

$\frac{5}{6} , \frac{2}{3} ,\frac{1}{2}, \frac{1}{3} ...$

First of all, we have to find the common difference

$here\\a_1 = \frac{5}{6}\\a_2 = \frac{2}{3}\\a_3 = \frac{1}{2}\\a_4 = \frac{1}{3}\\d = a_2-a_1 = \frac{2}{3} -\frac{5}{6} = \frac{4-5}{6} = -\frac{1}{6}\\d = a_3 - a_2 = \frac{1}{2} - \frac{2}{3} = \frac{3-4}{6} = =\frac{1}{6}$