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Marrrta [24]
3 years ago
15

Which statement is true about the graphed function?​

Mathematics
1 answer:
Viefleur [7K]3 years ago
4 0

<em>Greetings from Brasil....</em>

Remember that F(X) = Y

Looking at the graph we can conclude that:

Y > 0 when X < - 4<em> (up until -∞)</em>

Y = 0 when X = - 4

Y < 0 when X > - 4<em> (up until +∞)</em>

So choose:

[F(X) = Y]  > 0 over the interval ]-∞; -4[

<em>(last option)</em>

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Simplify the expression where possible.<br><br> (-5x2)^3
Paul [167]

Answer:

-1000

Step-by-step explanation:

1. Do the Parenthesis problem first. (PEDMAS/PEMDAS)

You should then have -10^3

2. Solve with the exponent. (-10 x 10 x 10)

You should then get your final answer, which is -1000.

Any Questions/Concerns?

6 0
3 years ago
9) 4 = K/42<br> Solve that for me pls I’m writing here because I need twenty words
DaniilM [7]

Answer:

k = 168

Step-by-step explanation:

4= \frac{k}{42} rewrite the equation

42 * 4=\frac{k}{42} *42 Multiply 42 to isolate k. Do the same on the other side

42 * 4 = 168 When you do that you get 168.

8 0
3 years ago
Determine the scale factor of the diagram
Leno4ka [110]
5 cm de longitud de eso
8 0
3 years ago
How do we find the missing side of a shape when we are given the perimeter?
ryzh [129]

Answer:

subtract the inside number's

Step-by-step explanation:

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4 0
3 years ago
The rectangle below has an area of 1 8 x 3 18x 3 square meters and a length of 2 x 2 2x 2 meters.
motikmotik

Answer:

\text{The width of rectangle}=9x\text{ meters}

Step-by-step explanation:

We have been given that the rectangle has an area of 18x^3 square meters and a length of 2x^{2}. We are asked to find the width of rectangle.

Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.

\text{Area of rectangle}=\text{Width of rectangle *Length of the rectangle}

\frac{\text{Area of rectangle}}{\text{Length of rectangle}}=\frac{\text{Width of rectangle *Length of the rectangle}}{\text{Legth of rectangle}}

\text{The width of rectangle}=\frac{\text{Area of rectangle}}{\text{Length of rectangle}}

Upon substituting our given values in above formula we will get,

\text{The width of rectangle}=\frac{18x^3\text{ meter}^2}{2x^2\text{ meters}}

\text{The width of rectangle}=\frac{9x^3\text{ meters}}{x^2}

Using exponent rule for quotient \frac{a^m}{a^n}=a^{m-n} we will get,

\text{The width of rectangle}=9x^{3-2}\text{ meters}

\text{The width of rectangle}=9x^{1}\text{ meters}=9x\text{ meters}

Therefore, width of our given rectangle will be 9x meters.

3 0
2 years ago
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