This is tricky
lets try substituting y = √)6x - 9)
√(6 - y) + √(6x + y) = √6
squaring both sides:-
6 - y + 6 + y - 2√(6 - y)(6 + y) = 6
12 - 2√(6 - y)(6 + y) = 6
√(6 - y)(6 + y) = (6-12) / -2 = 3
Squaring both sides:-
(6 - y)(6 + y) = 9
36 - y^2 = 9
y^2 = 27
y = +/-√27
√(6x - 9) = +/- 27
6x - 9 = 729
x = 738/6 = 123
This cannot be a solution because we would have a negative value for the
second square root
I would say that no solution exist.
The answer is: [A]: " 20a − 5b − 9 " .
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Explanation:
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(12a <span>+ 7b) + (−6a − 9) + (14a − 12b) =
12a </span><span>+ 7b + 1(−6a − 9) + 1(14a − 12b) =
</span>
12a + 7b + (1*-6a) + (1*-9) + (1*14a) + (1* -12b) =
12a + 7b − 6a − 9 + 14a − 12b = ?
Combine the "like terms:
12a − 6a + 14a = 20a ;
7b − 12b = - 5b ;
and then we have "-9" ;
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So, write as: " 20a − 5b − 9 " ; which is: Answer choice: [A].
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Answer:6x+9y=75
Step-by-step explanation:
Answer:
the number of times Angela needs to fill the 1/4-cup measuring cup to pour 1/2 cup of milk is 2.
Complete question:
While making oatmeal cookies, Angela needs to add 1/2 cup of milk to her dough. However, she has only a 1/4-cup measuring cup. How many times does she need to fill the measuring cup to pour 1/2 cup of milk? The number of times Angela needs to fill the 1/4-cup measuring cup to pour 1/2 cup of milk is?
Step-by-step explanation:
Number of cups Angela needs to add to her dough = 1/2 cup of milk
The only measuring cup she has = 1/4-cup measuring cup.
To determine the number of times she needs to fill the measuring cup to pour 1/2 cup of milk, we would divide the 1/2 cup of milk by 1/4-cup measuring cup
= ½ ÷ ¼
= ½ × 4/1
= 4/2
= 2
Angela would need to fill 2 times
Therefore, the number of times Angela needs to fill the 1/4-cup measuring cup to pour 1/2 cup of milk is 2
Answer:
Attached diagram A'B'C'D'
Step-by-step explanation:
Given is a quadrilateral ABCD. It says to draw a dilated version with a scale factor 2/3.
We see that scale factor is less than 1 which means it shrinks the image to a smaller one.
To draw a scaled copy, we need to find the lengths of its sides.
To do so, we can draw the diagonals AC & BD, and they intersect at origin O(0,0) such that OA= -2, OB= 2, OC= 4, OD= -4.
Applying a scale factor of 2/3, we get OA' = -4/3, OB' = 4/3, OC' = 8/3, OD' = -8/3.
So we have attached a scaled copy A'B'C'D' of quadrilateral ABCD with a scale factor 2/3.
