Answer:
This means that the means height (which is all the sum of the height of all the students divided by their number ) is 205 cm. Standard deviation means how the height of the students deviates from this mean since students do vary in height and are not all the same height of 205 cm. Therefore, in this case, the amount of standard dispersion of the students' height is by 17 cm on either lower or higher side of the mean.
Vegetable oil is........................the phospholipids in vegetable oil have fatty acid tails that ARE BEND.
Vegetable oil are made up of unsaturated fatty acids, which means that double bonds are present in the oil. The degree of unsaturation varies depending on the type of oil. The configuration for double bond is cis; this makes the phospholipid in the vegetable oil to have bent structure.
The similarity between directional and disruptive is that both are types of selection on polygenic traits in which the curve shift away from the middle.
The different between disruptive and directional is in disruptive move toward both ends . And in directional, the curve shift toward one end.
Answer:
Option A
Explanation:
The genotypic frequency for tt (q²) = 36% = 36/100 = 0.36
To calculate for the allelic frequency of t which is q, we have to find the square root of q² to do this. Thus
√q² = √0.36 = 0.6 this q = 0.6
The allelic frequency p for the T allele can then be calculated using this formula p + q = 1
Where q is 0.6 thus p= 1 - 0.6 = 0.4.
This the allelic freq of T is 0.4
Answer: The probability that individual 1 is heterozygous is 1.
The probability that individual 3 is heterozygous is 1.
The probability that individual 4 is affected is 0.
Explanation: Since the father was said to be affected, the genotype of the father will be homozygous recessive. Using (A) to represent the dominant allele and (a) to represent the recessive allele, we can say that the father's genotype is aa.
Since the genotype of the mother was not given, we assume that she has wild-type genotype which is homozygous dominant allele because no contrary information was given. We can then say that her genotype is AA.
A cross between aa and AA will produce offspring with genotype Aa only. Therefore, we can conclude that 1 - 4 have heterozygous alleles.
Check the attached image for better illustration.
