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Vsevolod [243]
3 years ago
8

I need help with that

Mathematics
1 answer:
wariber [46]3 years ago
5 0
I hope this helps you square root of 11 irrational -7 negative integer 47/10 rational 4,1=41/10 rational -5 negative integer square root of 16= 4 real
You might be interested in
Four gallons of gasoline cost $16.80. What is the price per gallon (also known as the slope of the line)?
il63 [147K]

$16.80 / 4 gallons = $4.20 per gallon

5 0
3 years ago
Find an equivalent fractions<br> for each given fraction<br> 70/10
ivanzaharov [21]

Answer:

140/20

Step-by-step explanation:

If you reduce the fraction your left with just 7

7 0
3 years ago
Help!
Olin [163]

Answer:

2/16

1/8

Step-by-step explanation:

8/1=8

2/16=0.125 which is equal to 1/8

2/14=1/7

1/8=1/8 is 2/16 simplified so they are the same

14/2=7

6 0
3 years ago
Which function is increasing at the highest rate? A. B. A linear function on a coordinate plane passes through (minus 1, 3), and
xenn [34]

The highest rate on increasing is of 12x -6y = -24; Option B is the correct answer.

The options are given in the image attached with the answer

<h3>What is a Function ?</h3>

A function is a law that relates a dependent variable and an independent variable.

It is asked among the options given , which is increasing at the highest rate.

To increase at a rate , the value of the slope , m should be > 0

For the Option 1

for a straight line function , the slope is given by

m = ( y₂ -y₁)/(x₂-x₁)

m = ( -3 -3)/(2- (-1)) = -6 /3 = -2

Therefore the function is decreasing

For Option 2

12x - 6y = -24

-6y = -12x -24

y = 2x +4

m = 2 (increasing)

For option 3

m = (-4 + 5)/(2-1) = 1

For Option 4

(8,0) (0,-4)

m = (-4 -0) /(0-8) = 4/8 = 1/2

The highest rate on increasing is of 12x -6y = -24

Therefore Option B is the correct answer.

To know more about Function

brainly.com/question/21145944

#SPJ1

6 0
2 years ago
Find the slope of each line <br> 9,4,-1,-6
marusya05 [52]

Answer: slope is 1

Step-by-step explanation:

-6-4= -10

-1-9 = -10

4 0
3 years ago
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