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2 years ago

I need help with that

Mathematics

1 answer:

wariber [46]2 years ago

5 0

I hope this helps you square root of 11 irrational -7 negative integer 47/10 rational 4,1=41/10 rational -5 negative integer square root of 16= 4 real

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How do i get a fraction and as a decimal for 72%full

garik1379 [7]

Move the decimal twice to the right to get a decimal (it should start behind the 2 and end up in front of the 7)
For a fraction just put it over 100 72/100

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2 years ago

Manny and Evan were flying paper airplanes. Manny’s airplane flew 36.5 centimeters and Evan’s airplane flew 18 centimeters. How

professor190 [17]

First subtract manny value 36.5 from Evan values 18 which will give u 18.5 cm which then u have to convert. Since 1 cm is about .4, we can multiply 18.5 by .4 to get the answer 7.4 inches

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3 years ago

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I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have

$i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079$

3 0

2 years ago

Please help me with thisss

Solnce55 [7]

Answer:

(x, y) = (-2, -3)

WORK:

2x + 4y = -16 =

-2x + 2y = -2 =

(^ the two’s cancel out) =

6y = -18 =

(^ you need to divide 6 on both sides to get just y) =

6y/6 = -18/6 =

(^ the six’s cancel out) =

y = -3 =

(^ now you have to plug this in to get x) =

2x + 4(-3) = -16 =

2x - 12 = -16 =

(^ you need to add 12 on both sides to get rid of it on the left side to add it to -16 on the right side) =

2x = -4 =

2x/2 = -4/2 =

(^ now you divide 2 on both sides again to get just y, and they will cancel out) =

x = -2 =

THEREFORE YOU GET (-2, -3)

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2 years ago

Using capital letters and no periods or spaces, type the abbreviation for the congruence postulate.

jek_recluse [69]

HL is the answer got it from answer key

6 0

2 years ago

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