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Alexeev081 [22]
3 years ago
13

Lim x->0 of tan6x/sin2x ?

Mathematics
1 answer:
jonny [76]3 years ago
7 0
The limit of the function tan 6x/sin 2x as x approaches zero is determined by first substituting x by zero. This is equal to zero over zero which is indeterminate. Using L'hopital's rule, we derive each term in the numerator and denominator separately. This is equal to 6 sec^2 x / 2 cos 2x. when substituted with zero again, the limit is 1/2.
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worty [1.4K]

Answer:

495

Step-by-step explanation:

pete=178

sharon=178+119=297

297+178=495

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Which operation should be performed first according to the order of operations?
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4 0
3 years ago
Suppose X has a continuous uniform distribution over the interval [−2,2]
Sliva [168]

Answer:

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b) \int\limits^a_b f({x}) \, dx=  \int\limits^a_a {\frac{1}{a- (-a)} } \, dx

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P(−a<X<a) =\int\limits^a_b {x} \, dx=1/2 * 2a= a    (applying the limits to the function)

P(−a<X<a)= 0.9

a= 0.9

In the given question the limits are -a to a . When we apply these in the above instead of [a,b] we get the above answer.

8 0
4 years ago
If the circumference of a circle is 201 centimeters what is the radius of the circle (to the nearest whole number)? Use 3.14 for
saul85 [17]
Formula for circumference:  C = 2pi*r

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Divide both sides of this eqn by 6.28:

201
------- = r  = 32 cm (approx).
6.28 
7 0
3 years ago
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