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katovenus [111]

3 years ago

10

COME ON JESUS PEOPLE RAISE YOUR HALLELUJAH. MY REAL NAME IS CHKAWOLF CHARIS GRACE ELIZIBETH SERLE AND I AM A CHILD OF THE ONE TR

UE GOD
WHO'S ARE YOU . AND CHIKA MEANS GOD IS GREATEST SHARE THIS

1 answer:

podryga [215]3 years ago

4 0

Answer: i don't think that this is a school question please ask school related questions have a great day

Step-by-step explanation:

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Which of the following expressions are equivalent to 3(4h + 2k) ?

nordsb [41]

Answer:

B, C, and D are all equivalent to 3(4h+2k)

Step-by-step explanation:

We use the distributive property to say 3(4h+2k)=12h+6k

"A" distributes to 12k+6h

"B" distributes to 12h+6k

"C" distributes to 6k+12h (associative property works)

"D" is already distributed to 12h+6k

So A is wrong, and B, C, and D are right

Hope this made sense!

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3 years ago

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75 * .36 = 27 men

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3 years ago

-3 - 3х2 – 4x factor

Vlad1618 [11]

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Step-by-step explanation:

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Step-by-step explanation:

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5 0

3 years ago

Prove the following identity showing all steps:

kiruha [24]

Answer:

See solution below

Step-by-step explanation:

Given the expression

$\frac{cos(x+30)-sin(x+60)}{sin(x)cos(x)} \\$

Recall that

cos x = sin(90-x)

cos(x+30 ) = sin (90-(x+30)

= sin(90-x-30)

= sin(60-x)

Substitute

$\frac{sin(60-x)-sin(x+60)}{sin(x)cos(x)} \\= \frac{sin60cosx-cos60sinx)-sinxcos60-cosxsin60)}{sin(x)cos(x)} \\= \frac{-2cos60sinx)}{sin(x)cos(x)} \\= \frac{-2(1/2)sinx)}{sin(x)cos(x)} \\= \frac{-1}{cos(x)}\\= \frac{1}{cos(x)}\\ \\= -sec(x) Proved$

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3 years ago