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saul85 [17]
3 years ago
11

Kia is printing packets of information. There are 23 pages in a packet, and she needs enough copies for 52 people. Each package

of paper contains 200 sheets. She estimates she needs 5 packages of paper to print the packets. Will she have enough paper? Explain.
Mathematics
1 answer:
Andrew [12]3 years ago
6 0
No she will not have enough paper because 200 times five is 1000 and if you multiply 23 by 52 is 1196 but I am not fully sure if this answer is right
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72.3 + (-39.1)
joja [24]

Answer:

72.3 - 39.1 = 4tens - 7ones + 2tenth

Step-by-step explanation:

Give the expression 72.3 + (-39.1)

opening the parenthesis:

= 72.3 + (-39.1)

= 72.3 - 39.1

Breaking the decimal values into place values

72.3 = 7tens + 2units + 3tenth

72.3 = 7(10)+2(1)+3(1/10)

72.3 =70+2+0.3

Similarly for 39.1

39.1 = 3tens + 9units + 1tenth

39.1 = 3(10)+9(1)+1(1/10)

39.1 =30+9+0.1

72.3 - 39.1 = 70+2+0.3 - (30+9+0.1)

72.3 - 39.1 = 70+2+0.3 - 30-9-0.1

72.3 - 39.1  = 70-30+2-9+0.3-0.1

72.3 - 39.1 = 40 - 7 +0.2

72.3 - 39.1 = 4tens - 7ones + 2tenth

3 0
3 years ago
Which choices are equivalent to the expression below
arsen [322]

Answer:

Gotta give the image

Step-by-step explanation:

Bdndbdjddbdhd dvdn d dbd

4 0
3 years ago
While driving past stores, Tatum counted the number of cars in the parking lots.
Vlad [161]

Answer:

9

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
A particular psychological test is used to measure need for achievement. The average test score for all university students in O
Angelina_Jolie [31]

Answer:

Only B and C are always true.

Step-by-step explanation:

To analyse which statements are always true, we go through the process of finding confidence intervals for sample means, from the start.

Confidence Interval = (Sample mean) ± (Margin of error)

From this expression, it is evident that the margin of error determines how wide the confidence interval would be.

Sample Mean = 110 (given)

Margin of Error = (Critical value) × (Standard deviation of the distribution of sample means)

Since no information about the population standard deviation is provided, the critical value is obtained using t-distribution.

The critical value usually varies at different confidence levels and degree of freedoms.

The higher the confidence level, the higher the critical value and the higher the margin of error leading to a wider range.

Hence, a confidence interval of 95% will have a higher critical value than a confidence interval of 90%. Hence, statement C is proved once that 'for n = 100, the 95% confidence interval will be wider than the 90% confidence interval'.

After obtaining the critical value, we then obtain the standard deviation of the distribution of sample means or simply the standard error of the mean. This is given as

σₓ = σ/√n

where σ = standard deviation; which isn't given. The standard deviation might be high enough to guarantee that the Margin of error is high too for the confidence interval to contain 115 or low enough to ensure that the Margin of error is very small and the confidence interval will not contain 115.

Or the sample size might be high enough to make the standard error of the mean to be eventually small and lead to a small margin of error and the condidence interval will not contain 115.

The point is, it isn't always sure that the resulting interval.would contain 115. So, statement A isn't always true.

Then from σₓ = σ/√n,

n = sample size, a large sample size means a more narrow confidence interval and a small sample size means a wider sample size. This proves statement C.

The 95% confidence interval for n = 100 will be more narrow than the 95% confidence interval for n = 50.

Hence, Only B and C are always true.

Hope this Helps!!!

5 0
3 years ago
a guy is washing 32 feet off the ground. he positions the ladder at an angle of 67° with the ground. how tall is the ladder
irina [24]

Answer:

34.76 feet

Step-by-step explanation:

trig

SOH CAH TOA

6 0
3 years ago
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