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vredina [299]
3 years ago
10

Find, corrrect to the nearest degree, the three angles of the triangle with the given vertices. D(0,1,1), E(-2,4,3), C(1,2,-1)

Mathematics
1 answer:
Sholpan [36]3 years ago
4 0

Answer:

The three angles of the triangle given above are 23, 73 and 84 correct to the nearest degree. The concept of dot product under vectors was applied in solving this problem. The three positions forming the triangle were taken as positions vectors. The Dot product also known as scalar product is a very good way of finding the angle between two vectors. ( in this case the sides of the triangle given above). Below is a picture of the step by step procedure of the solution.

Step-by-step explanation:

The first thing to do is to treat the given positions in space as position vectors which gives us room to perform vector manipulations on them. Next we calculate the magnitude of the position vector which is the square root of the sun of the square of the positions of the vectors along the three respective axes). Then we calculate the dot product. After this is calculated the angle can then be found easily using formula for the dot product.

Thank you for reading this and I hope it is helpful to you.

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I bought a TV. the screen is 52 inches wide and 29 inches high. find the length of its diagonal.​
Crank

Answer:

*3545*

Step-by-step explanation:

52 square + 29 square = 3545

then square root 3545 = 59.539 ( round it if you want)

6 0
2 years ago
F(x)=3x+2 and g(x)=-2x-4, find h(x)= f(x)-g(x)
Katena32 [7]


substitute for your equation;

h(x) = f(x) - g(x)

h(x) = (3x + 2) - (-2x -4)

h(x) = 3x + 2 + 2x + 4 (minus and minus = addition)

h(x) = 3x + 2x + 2 + 4 (combine like terms)

h(x) = 5x + 6

Hope that helps! :D

8 0
2 years ago
Without using a trigonometric ratio, find the distance from the ship to the buoy, B. Round the distance to the nearest tenth of
alexdok [17]
Without using the trigonometry ratio, we can find the distance between the ship and the buoy by:

the distance between City and Lemont SUBTRACT the vertical distance between City and the point parallel to the Ship

The distance between the City and Lemont can be worked out using the Sin rule 
\frac{57.8}{sin(36)}= \frac{City-Lemont}{sin(92)}
City-Lemont= \frac{57.9sin(92)}{sin(36)} = 98.27.....≈98.3

The vertical distance between the City and the point parallel to the ship can be worked out using the Pythagoras theorem
\sqrt{57.8^{2}- 44.6^{2} } =36.765...≈36.8

The distance between the ship and the Buoy is given:
98.3-36.8=61.5 miles

5 0
2 years ago
If the point of the preimage is (5,2) and the point of the image is (1,2), what RULE was applied to the preimage to obtain the i
marusya05 [52]
<h3>Answer: Choice C)  (x-4, y)</h3>

Explanation:

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The y coordinate stays at y = 2 the entire time, so y isn't altered. We have y map to y.

Overall, the rule is (x,y) \to (x-4, y) which translates the point 4 units to the left.

5 0
3 years ago
Help! Please help me answer this question!
Harrizon [31]
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6 0
2 years ago
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