The answer for what is NOT true would be..
B. A sequence is a function whose domain is the set of real numbers.
&
C. A function is a relation in which each value of the input variable is paired with exactly one value of the output variable.
I hope this helps have a great day.
we have
![3x^{2} -8x+5](https://tex.z-dn.net/?f=3x%5E%7B2%7D%20-8x%2B5)
Equate the expression to zero to find the roots
![3x^{2} -8x+5=0](https://tex.z-dn.net/?f=3x%5E%7B2%7D%20-8x%2B5%3D0)
Group terms that contain the same variable, and move the constant to the opposite side of the equation
![3x^{2} -8x=-5](https://tex.z-dn.net/?f=3x%5E%7B2%7D%20-8x%3D-5)
Factor the leading coefficient
![3(x^{2} -(8x/3))=-5](https://tex.z-dn.net/?f=3%28x%5E%7B2%7D%20-%288x%2F3%29%29%3D-5)
Complete the square. Remember to balance the equation by adding the same constants to each side.
![3(x^{2} -(8x/3)+(16/9))=-5+(16/3)](https://tex.z-dn.net/?f=3%28x%5E%7B2%7D%20-%288x%2F3%29%2B%2816%2F9%29%29%3D-5%2B%2816%2F3%29)
![3(x^{2} -(8x/3)+(16/9))=(1/3)](https://tex.z-dn.net/?f=3%28x%5E%7B2%7D%20-%288x%2F3%29%2B%2816%2F9%29%29%3D%281%2F3%29)
Rewrite as perfect squares
![3(x-(4x/3))^{2}=(1/3)](https://tex.z-dn.net/?f=3%28x-%284x%2F3%29%29%5E%7B2%7D%3D%281%2F3%29)
![(x-(4x/3))^{2}=(1/9)](https://tex.z-dn.net/?f=%28x-%284x%2F3%29%29%5E%7B2%7D%3D%281%2F9%29)
square roots both sides
![(x-\frac{4}{3})=(+/-) \sqrt{\frac{1}{9}}](https://tex.z-dn.net/?f=%28x-%5Cfrac%7B4%7D%7B3%7D%29%3D%28%2B%2F-%29%20%5Csqrt%7B%5Cfrac%7B1%7D%7B9%7D%7D)
![x=\frac{4}{3}(+/-) \frac{1}{3}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B4%7D%7B3%7D%28%2B%2F-%29%20%5Cfrac%7B1%7D%7B3%7D)
the roots are
![x=\frac{4}{3}+ \frac{1}{3}=\frac{5}{3}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B4%7D%7B3%7D%2B%20%5Cfrac%7B1%7D%7B3%7D%3D%5Cfrac%7B5%7D%7B3%7D)
![x=\frac{4}{3}- \frac{1}{3}=\frac{3}{3}=1](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B4%7D%7B3%7D-%20%5Cfrac%7B1%7D%7B3%7D%3D%5Cfrac%7B3%7D%7B3%7D%3D1)
so
![3x^{2} -8x+5=3(x-\frac{5}{3})(x-1)=(3x-5)(x-1)](https://tex.z-dn.net/?f=3x%5E%7B2%7D%20-8x%2B5%3D3%28x-%5Cfrac%7B5%7D%7B3%7D%29%28x-1%29%3D%283x-5%29%28x-1%29)
therefore
<u>the answer is the option</u>
![(3x-5)(x-1)](https://tex.z-dn.net/?f=%283x-5%29%28x-1%29)
First, to estimate we can round 53.82 up to 55.00. Then you can look at it like this: when you divide 100 by 20 you get 5, so 20% is one fifth of 100. Therefore, we want to find one fifth of $55. To do this, you multiply 55*1/5. When you multiply the numerators by each other and the denominators by each other, you get 55/5. When you divide the numerator and denominator by 5, you get 11/1 or $11.
Hope this helps
Hello :
f(x) = <span>√(0.5x-10) +3
</span>inequality can be used to find the domain of f(x) is : 0.5x-10 <span>≥ 0
</span>0.5x ≥10
x ≥10/0.5
x ≥ 20
the domain of f(x) is : D = <span>[</span><span>20 ; + ∞[ </span>
Answer:
negative reciprocals of each other