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Tems11 [23]
3 years ago
11

An isotope decays at a rate of -0.0049% per year. Find the half life. (show the work)

Mathematics
1 answer:
cricket20 [7]3 years ago
7 0

Answer:

  14,146 years

Step-by-step explanation:

The annual multiplier is (1 -0.0049%) = 0.999951. We want to find the number of times this needs to be multiplied to make the product 1/2.

  0.5 = 0.999951^t

  log(0.5) = t·log(0.999951)

  log(0.5)/log(0.999951) = t ≈ 14,145.514

The half-life is about 14,146 years.

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