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cupoosta [38]
2 years ago
15

How to find the value of x in each figure?​

Mathematics
2 answers:
mezya [45]2 years ago
7 0

You need to multiply the length and the width of the shape.

Maksim231197 [3]2 years ago
5 0

There are many different formulas, it depends on what shape it is. So what shape do you need to solve for?

You might be interested in
F(x)=-5x
vlada-n [284]

Answer: D. -40x^3 + 25x^2 + 45x

Step-by-step explanation:

-5x(8x^2 - 5x - 9)

-40x^3 + 25x^2 + 45x

7 0
3 years ago
Actor the expression 16x+8x+1 16x 28x +11-​
Gwar [14]
<h3>Explanation:</h3>

\large \purple {\sf { {16x}^{2}  + 8x + 1}}

\large \pink {\sf { =  {(4x)}^{2}  + 2(4x)(1) +  {(1)}^{2}}}

\large \orange {\sf { = {(4x + 1)}^{2} }}

<h2>Answer:</h2>

\large \green {\sf {{16x}^{2}  + 8x + 1 =  {(4x + 1)}^{2}}}

6 0
2 years ago
it cost $5 for a snow cone. which function rule correctly relates the number of snow cones purchase , s,to the cost, c
Shtirlitz [24]
Each cones is $5 so to get the total cost, you would multiple $5 by the number of cones sold so that would be c = 5s

Final answer: c = 5s
8 0
3 years ago
Read 2 more answers
Need help!! Don't understand algebra.<br> I need help figuring out 18x2 + 9x - 20
Murrr4er [49]
The answer is (6x-5)(3x+4)

Write 9x as a sum or difference.
18x^2+24x-15x-20
Factor out 6x from the expression.
18x^2+24x
Factor out -5 from the expression.
-15x-20
Factor out 3x+4 from the expression. 
6x(3x+4)-5(3x+4). 

8 0
3 years ago
Your digital camera has a 512 megabyte memory card. You take pictures at two resolutions, a low resolution requiring 4 megabytes
____ [38]

One possible answer is 8H + 4L = 512

=======================================================

Explanation:

  • H = number of high resolution photos
  • L = number of low resolution photos

H and L are placeholders for positive whole numbers, or 0 could replace either variable.

1 high resolution photo takes up 8 mb of space, so H of them take up 8H megabytes of space.

1 low resolution photo takes up 4 mb of space, so L of them take up 4L megabytes.

Overall, the two types of photos take up 8H+4L megabytes, which is equal to 512 since that's the max capacity. That leads to the equation 8H+4L = 512

----------------------------------

Extra info:

There are other ways to express the equation 8H+4L = 512. We could divide each part by 4 to get 2H+L = 128, but I think this equation loses its descriptive quality in a way. We no longer can see that each high resolution photo takes up 8 megabytes (instead we might mistakenly think only 2 megabytes are used per high resolution photo). A similar mistake may happen with the low resolution photos also.

The equation 2H+L = 128 can be rearranged into L = -2H+128 when solving for L.

6 0
3 years ago
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