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devlian [24]
3 years ago
12

5 1/5 - 3 4/7 = A. 2 3/4 B. -2 3/4 C. 1 16/21 D. -1 16/21

Mathematics
1 answer:
matrenka [14]3 years ago
4 0
116/21 hope this helped !
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Answer:

For the sequence is -\frac{2}{3} ,-4 ,-24 ,-144 ,...

Hence the formula f(x)=-\frac{2}{3}(6)^{x-1} for x=1,2,3,... represents the given geometric sequence

Step-by-step explanation:

Given sequence is -\frac{2}{3} ,-4 ,-24 ,-144 ,...

To find the formula to describe the given sequence :

Let a_1=\frac{-2}{3} ,a_2=-4 ,a_3=-24,...

First find the common ratio

r=\frac{a_2}{a_1} here  a_1=\frac{-2}{3} and,a_2=-4

=\frac{-4}{\frac{-2}{3}}

=\frac{4\times 3}{2}

=\frac{12}{2}

r=6

r=\frac{a_3}{a_2} here  a_2=-4 and a_3=-24

=\frac{-24}{-4}

=6

r=6

Therefore the common ratio is 6

Therefore the given sequence is geometric sequence

The nth term of the geometric sequence is

a_n=a_1r^{n-1}

The formula which describes the given geometric sequence is

f(x)=a_1r^{x-1} for x=1,2,3,...

=\frac{-2}{3}6^{x-1} for x=1,2,3,...

Now verify that f(x)=a_1r^{x-1} for x=1,2,3,... represents the given geometric sequence or not

put x=1 and the value of a_1 in f(x)=a_1r^{x-1} for x=1,2,3,...

we get f(1)=-\frac{2}{3}(6)^{1-1}

=-\frac{2}{3}(6)^0

=-\frac{2}{3}

Therefore f(1)=-\frac{2}{3}

put x=2 we get f(2)=-\frac{2}{3}(6)^{2-1}

=-\frac{2}{3}(6)^1

=-\frac{12}{3}

Therefore f(2)=-4

put x=3 we get f(3)=-\frac{2}{3}(6)^{3-1}

=-\frac{2}{3}(6)^2

=-\frac{2(36)}{3}

Therefore f(3)=-24

Therefore the sequence is f(1),f(2),f(3),...

Therefore  the sequence is -\frac{2}{3} ,-4 ,-24 ,-144 ,...

Hence the formula f(x)=a_1r^{x-1} for x=1,2,3,... represents the given geometric sequence is verified

Therefore the formula f(x)=-\frac{2}{3}(6)^{x-1} for x=1,2,3,... represents the given geometric sequence

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Answer:

Area= 32 (formula is: length x width)

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Step-by-step explanation:

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1- faster 2- rises,sink 3-equater 4-convection idk the rest

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